Mysql 将不同的表处理为IF

我想根据每个参数收到的值选择一个表。有没有可能像我的代码那样做呢？多谢各位

/*程序*/

BEGIN
    DECLARE text varchar(30);

    IF (type = 1) THEN  
        SET text = 'table1';
    ELSEIF (type  = 2) THEN
        SET text = 'table2';        
    ELSEIF (type  = 3) THEN
        SET text = 'table3';        
    ELSEIF (type  = 4) THEN
        SET text = 'table4';                
    END IF;

    Select * from text where `fee type` = var2;

END

BEGIN
    DECLARE text varchar(30);

    IF (type = 1) THEN  
        SET text = 'table1';
    ELSEIF (type  = 2) THEN
        SET text = 'table2';        
    ELSEIF (type  = 3) THEN
        SET text = 'table3';        
    ELSEIF (type  = 4) THEN
        SET text = 'table4';                
    END IF;

    SET @s = CONCAT('Select * from ',text,' where `fee type` = ?')
    PREPARE sentence FROM @s;
    SET @var1 = 2;
    EXECUTE sentence USING @var1;
    DEALLOCATE PREPARE sentence ;

END

---

查询与表的名称连接在一起，并在PREPARE中使用

/*程序*/

BEGIN
    DECLARE text varchar(30);

    IF (type = 1) THEN  
        SET text = 'table1';
    ELSEIF (type  = 2) THEN
        SET text = 'table2';        
    ELSEIF (type  = 3) THEN
        SET text = 'table3';        
    ELSEIF (type  = 4) THEN
        SET text = 'table4';                
    END IF;

    Select * from text where `fee type` = var2;

END

BEGIN
    DECLARE text varchar(30);

    IF (type = 1) THEN  
        SET text = 'table1';
    ELSEIF (type  = 2) THEN
        SET text = 'table2';        
    ELSEIF (type  = 3) THEN
        SET text = 'table3';        
    ELSEIF (type  = 4) THEN
        SET text = 'table4';                
    END IF;

    SET @s = CONCAT('Select * from ',text,' where `fee type` = ?')
    PREPARE sentence FROM @s;
    SET @var1 = 2;
    EXECUTE sentence USING @var1;
    DEALLOCATE PREPARE sentence ;

END

---

您尝试这样做的Google“mysql准备语句”强烈表明您的模式违反了规则。最好有一个单独的表，带有一个（索引的）列，其中包含一个指示符（例如字符串

'table1'

等），该指示符根据您的需要区分数据。