MySQL：如何计算按天/小时分组的分钟行

我的选择非常有效，只是每小时的计数相同：

SQLfiddle：

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我相信这应该是你需要的：

SELECT
  sh.player,
  sh.day,
  sh.hour,
  act.count_minutes minutes,
  ((act.count_minutes / 60) * 100) AS percent_of_hr
FROM (SELECT
  player,
  MONTH(datetime) amonth,
  DAY(datetime) aday,
  HOUR(datetime) ahour,
  COUNT(*) count_minutes
FROM activity
GROUP BY player,
         MONTH(datetime),
         DAY(datetime),
         HOUR(datetime)) act
RIGHT JOIN (SELECT DISTINCT
  a.player,
  s.hour,
  DAY(a.datetime) day,
  MONTH(a.datetime) month
FROM activity a
CROSS JOIN stub_hours s) sh
  ON act.ahour = sh.hour
  AND act.player = sh.player
  AND act.aday = sh.day
  AND act.amonth = sh.month
ORDER BY sh.player, sh.day, sh.hour;

---

如果您需要不同的输出，请告诉我

你期望的结果是什么？看看这个：。它应该在一些方面有所帮助，但不是解决方案。发布你的预期结果，我可以试着帮你实现。哇，非常感谢你的帮助，克林诺，这很有效！我没想到会有三个问题。你解决这个问题的方式很有趣，我还在仔细阅读，但我想说声谢谢，它正是我需要的方式。

select 
    player, 
    day(datetime) as Day,
    stub.hour,
    hour(datetime) as Hour, 
    count(player) as minutes,
    ((count(player) / 60) * 100) as percent_of_hr
 FROM stub_hours as stub
 LEFT JOIN activity
  on Hour=stub.hour
    GROUP BY date_format( datetime, '%Y%m%d%h' ), Day, Hour, player
    ORDER BY player, datetime desc, Day, hour, minutes desc;

SELECT
  sh.player,
  sh.day,
  sh.hour,
  act.count_minutes minutes,
  ((act.count_minutes / 60) * 100) AS percent_of_hr
FROM (SELECT
  player,
  MONTH(datetime) amonth,
  DAY(datetime) aday,
  HOUR(datetime) ahour,
  COUNT(*) count_minutes
FROM activity
GROUP BY player,
         MONTH(datetime),
         DAY(datetime),
         HOUR(datetime)) act
RIGHT JOIN (SELECT DISTINCT
  a.player,
  s.hour,
  DAY(a.datetime) day,
  MONTH(a.datetime) month
FROM activity a
CROSS JOIN stub_hours s) sh
  ON act.ahour = sh.hour
  AND act.player = sh.player
  AND act.aday = sh.day
  AND act.amonth = sh.month
ORDER BY sh.player, sh.day, sh.hour;