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Mysql 在查询中重复使用计算_Mysql_Sql - Fatal编程技术网

Mysql 在查询中重复使用计算

Mysql 在查询中重复使用计算,mysql,sql,Mysql,Sql,我想在数据库中创建一个具有少量逻辑的视图。这是为了检查产品的可用性。我创建了一个简化的模式 但是,我需要在多个列中重复使用一个值。以下是我想做的: SELECT product.id AS id, SUM(IFNULL(purchase_product.amount,0)) AS amountSold, IFNULL(product.amountAvailable-amountSold,~0) AS amountAvailable, amountAvailable

我想在数据库中创建一个具有少量逻辑的视图。这是为了检查产品的可用性。我创建了一个简化的模式

但是,我需要在多个列中重复使用一个值。以下是我想做的:

SELECT
    product.id AS id,
    SUM(IFNULL(purchase_product.amount,0)) AS amountSold,
    IFNULL(product.amountAvailable-amountSold,~0) AS amountAvailable,
    amountAvailable>0 AS isAvailable,
FROM product
    LEFT JOIN purchase_product ON purchase_product.product_id = product.id
    LEFT JOIN purchase ON purchase.id = purchase_product.purchase_id AND purchase.completed = TRUE
GROUP BY product.id
但这失败了,因为我不能重复使用“amountsell”和“amountAvailable”。这使我可以选择重复计算或使用子查询(/加入SELECT/使用更多视图)


这是我能想到的最合理的折衷办法有更优雅的解决方案吗?

您可以在具有联接的子查询中执行此操作:

select product.id, s.amountsold,
       IFNULL(product.amountAvailable-s.amountSold,~0) AS amountAvailable, 
       product.amountAvailable>0 AS isAvailable
       -- although you probably mean
       -- IFNULL(product.amountAvailable-s.amountSold,~0) > 0 as isAvailable
from product join
     (SELECT product.id AS id, 
             SUM(IFNULL(purchase_product.amount,0)) AS amountSold,
             IFNULL(product.amountAvailable-amountSold,~0) AS amountAvailable, 
             amountAvailable>0 AS isAvailable
      FROM product LEFT JOIN
            purchase_product
            ON purchase_product.product_id = product.id LEFT JOIN
            purchase
            ON purchase.id = purchase_product.purchase_id AND
               purchase.completed = TRUE
      GROUP BY product.id
    ) t
    on product.id = t.id
在其他数据库中,可以使用windows函数执行类似操作。但是,mysql不支持它们


此外,我认为您希望在减去已售出的金额后可以使用isAvailable,因此我在中添加了它作为建议。

我非常喜欢您当前的解决方案,我认为它没有任何实际问题,但我认为这可能稍微简单一些:

SELECT  Product.ID, 
        COALESCE(AmountSold, 0) AS AmountSold,
        GREATEST(COALESCE(AmountAvailable, ~0) - COALESCE(AmountSold, 0), 0) AS AmountAvailable,
        COALESCE(AmountAvailable, ~0) - COALESCE(AmountSold, 0) > 0 AS IsAvailable
FROM    Product
        LEFT JOIN 
        (   SELECT  Product_ID, SUM(Amount) AS AmountSold
            FROM    Purchase_Product
                    INNER JOIN Purchase
                        ON Purchase.ID = Purchase_ID
            WHERE   Completed = 1
            GROUP BY Product_ID
        ) sold
            ON Sold.Product_ID = Product.ID;
唯一真正的变化是,我在子查询中删除了对product的引用,以减少表扫描的数量,并且稍微改变了计算的逻辑

最后,我在其中添加了
grest
,只是为了说明可能存在的任何数据完整性问题,这样您就永远不会有负面产品可用

您可以做进一步的子查询来增加查询的可读性,但这几乎肯定不会提高性能

显示稍微改进的执行计划