将所有子节点作为列从Sql Server中的XML返回
我将从XML字符串中选择节点,第一部分只是向您展示我从中选择的内容 问题是我想对各种不同的XML列执行此操作,并且我不想在select中为每一列指定节点名称,是否有方法自动将所有节点选择为列,或者使用count甚至光标将所有子节点作为列从Sql Server中的XML返回,sql,sql-server,xml,sqlxml,Sql,Sql Server,Xml,Sqlxml,我将从XML字符串中选择节点,第一部分只是向您展示我从中选择的内容 问题是我想对各种不同的XML列执行此操作,并且我不想在select中为每一列指定节点名称,是否有方法自动将所有节点选择为列,或者使用count甚至光标 DECLARE @MyXML XML SET @MyXML = (SELECT CAST ( '<AllowAdd>N</AllowAdd> <Allowed>NUMSEG</Al
DECLARE @MyXML XML
SET @MyXML = (SELECT
CAST (
'<AllowAdd>N</AllowAdd>
<Allowed>NUMSEG</Allowed>
<AllSegmentsEqualValue>N</AllSegmentsEqualValue>
<ClusterLevelSA>Y</ClusterLevelSA>
<ClusterLevelPremium>Y</ClusterLevelPremium>
<AllowAssignedAndInTrust>N</AllowAssignedAndInTrust>
<MinSegments>1</MinSegments>
<MaxSegments>100</MaxSegments>
<DefaultSegments>10</DefaultSegments>
<RoundPremiumsTo>2</RoundPremiumsTo>
<TaxDeferredAllowance>0.05</TaxDeferredAllowance>
<HigherTaxValueBands>HTVB</HigherTaxValueBands>
<NumberYearsCalculationType>NONFIN</NumberYearsCalculationType>
<OnShore>POLICY</OnShore>
<OffShore>NONFIN</OffShore>'as XML) as x)
SELECT
Data.Col.value('(/AllowAdd)[1]','Varchar(10)') as [Allow Addition of]
,Data.Col.value('(/Allowed)[1]','Varchar(10)') as [Allowed]
,Data.Col.value('(/MinSegments)[1]','Int') as [Min Segments]
,Data.Col.value('(/MaxSegments)[1]','Int') as [Max Segments]
,Data.Col.value('(/DefaultSegments)[1]','Int') as [Default Segments]
,Data.Col.value('(/RoundPremiumsTo)[1]','Int') as [Round Premiums To]
,Data.Col.value('(/AllSegmentsEqualValue)[1]','Varchar(10)') as [All Segments Equal Value]
--,Data.Col.value('(/TaxDeferredAllowance)[1]','Varchar(10)') as [Tax Deferred Allowance]
,Data.Col.value('(/HigherTaxValueBands)[1]','Varchar(10)') as [Higher Tax Value Bands]
,Data.Col.value('(/NumberYearsCalculationType)[1]','Varchar(10)') as [Number Years Calculation Type]
,Data.Col.value('(/OnShore)[1]','Varchar(10)') as [OnShore]
,Data.Col.value('(/OffShore)[1]','Varchar(10)') as [OffShore]
FROM @MyXML.nodes('/OffShore') AS Data(Col)
给定您的输入XML,您可以尝试使用以下方法:
SELECT
ColName = XC.value('local-name(.)', 'varchar(100)'),
ColValue = xc.value('(.)[1]', 'varchar(100)')
FROM
@MyXML.nodes('/*') AS XT(XC)
这将把根目录下的每个XML元素(其名称和值)作为列表输出:
当然,由于这是一种非常通用的方法,您无法真正为第二个xc.value中的每一列定义正确的数据类型-您基本上可以将所有内容都作为字符串来获取。使用光标构建SELECT语句,并使用sp_executesql来执行它
DECLARE @MyXML XML
DECLARE @FieldName VARCHAR(MAX)
DECLARE @SELECT_TEXT NVARCHAR(MAX)
SET @MyXML = (SELECT
CAST (
'<AllowAdd>N</AllowAdd>
<Allowed>NUMSEG</Allowed>
<AllSegmentsEqualValue>N</AllSegmentsEqualValue>
<ClusterLevelSA>Y</ClusterLevelSA>
<ClusterLevelPremium>Y</ClusterLevelPremium>
<AllowAssignedAndInTrust>N</AllowAssignedAndInTrust>
<MinSegments>1</MinSegments>
<MaxSegments>100</MaxSegments>
<DefaultSegments>10</DefaultSegments>
<RoundPremiumsTo>2</RoundPremiumsTo>
<TaxDeferredAllowance>0.05</TaxDeferredAllowance>
<HigherTaxValueBands>HTVB</HigherTaxValueBands>
<NumberYearsCalculationType>NONFIN</NumberYearsCalculationType>
<OnShore>POLICY</OnShore>
<OffShore>NONFIN</OffShore>
'
as XML) as x)
SET @SELECT_TEXT = 'SELECT '
DECLARE xml_cursor CURSOR
FOR SELECT Data.Col.value( 'fn:local-name(.)', 'VARCHAR(MAX)' ) FROM @MyXML.nodes('/*') AS Data(Col)
open xml_cursor
While 1 = 1
BEGIN
fetch next from xml_cursor into @FieldName
if @@fetch_status <> 0
begin
break
end
SET @SELECT_TEXT = @SELECT_TEXT + 'Data.Col.value(''(/' + @FieldName + ')[1]'',''Varchar(MAX)'') as [' + @FieldName + ']' + ', '
END
close xml_cursor
deallocate xml_cursor
SET @SELECT_TEXT = SUBSTRING( @SELECT_TEXT,0, LEN(@SELECT_TEXT) ) + 'FROM @MyXML.nodes(''/OffShore'') AS Data(Col)'
EXECUTE sp_executesql @SELECT_TEXT, N'@MyXML XML', @MyXML = @MyXML
正如前面在另一条评论中提到的,缺点是没有列类型,但它用于报告样式的查询,因此字符串是可以的。我希望,这就是您正在等待的:
DECLARE @MyXML XML
SET @MyXML = (SELECT
CAST (
'<AllowAdd>N</AllowAdd>
<Allowed>NUMSEG</Allowed>
<AllSegmentsEqualValue>N</AllSegmentsEqualValue>
<ClusterLevelSA>Y</ClusterLevelSA>
<ClusterLevelPremium>Y</ClusterLevelPremium>
<AllowAssignedAndInTrust>N</AllowAssignedAndInTrust>
<MinSegments>1</MinSegments>
<MaxSegments>100</MaxSegments>
<DefaultSegments>10</DefaultSegments>
<RoundPremiumsTo>2</RoundPremiumsTo>
<TaxDeferredAllowance>0.05</TaxDeferredAllowance>
<HigherTaxValueBands>HTVB</HigherTaxValueBands>
<NumberYearsCalculationType>NONFIN</NumberYearsCalculationType>
<OnShore>POLICY</OnShore>
<OffShore>NONFIN</OffShore>'as XML) as x)
DECLARE @Output nvarchar(max) = N''
DECLARE @PivotList nvarchar(max)
SELECT
@PivotList = COALESCE(@PivotList + ', ', N'') + N'[' + XC.value('local-name(.)', 'varchar(100)') + N']'
FROM
@MyXML.nodes('/*') AS XT(XC)
SET @Output = N'SELECT
'+@PivotList+N'
FROM
(
SELECT
ColName = XC.value(''local-name(.)'', ''nvarchar(100)''),
ColValue = ISNULL(NULLIF(CONVERT(nvarchar(max),XC.query(''./*'')),''''),XC.value(''.'',''nvarchar(max)''))
FROM
@MyXML.nodes(''/*'') AS XT(XC)
) AS s
PIVOT
(
MAX(ColValue)
FOR ColName IN ('+@PivotList+N')
) AS t;'
EXEC sp_executesql @Output, N'@MyXml xml', @MyXML = @MyXML;
但他希望得到列形式的值。需要一个动态的支点。是的,我自己做到了,见我的评论。它的动态,因为它可以得到!最好忽略将结果作为列获取的部分。应该是固定的elsewhere@JayCroghan是的,很有趣。我经常使用sql和xml。但还有一个问题——我发现了一个问题,不知道如何继续。包含XML的XML标记作为一列返回,不包含XML!例如:SET@MyXML=SELECT CAST“123”为XML,因为x将返回Tag1 Tag2 123@JayCroghan哪一个?@JayCroghan OMG,你只有一个XML结构吗?还是可以改变?多少层?这是个难题…我只需要第一个XML标记!任何更深的级别都可以作为XML字符串返回,因此在上面的Tag2示例中,值“23”是可以的!