Mysql 如何在Active Records Designer中进行多重加入
大家好,你们能帮我一下吗?我是数据库和Codeigniter的初学者。 如何在活动记录中编写此多个内部联接和左联接查询Mysql 如何在Active Records Designer中进行多重加入,mysql,codeigniter,activerecord,Mysql,Codeigniter,Activerecord,大家好,你们能帮我一下吗?我是数据库和Codeigniter的初学者。 如何在活动记录中编写此多个内部联接和左联接查询 SELECT suppliers.*, category.strCategory, category_1.strCategory AS strParent, tblcitylist.city_name FROM ((suppliers INNER JOIN category ON suppliers.intCat=Category.intId) INNER JOIN tblc
SELECT suppliers.*, category.strCategory, category_1.strCategory AS strParent,
tblcitylist.city_name
FROM ((suppliers INNER JOIN category ON suppliers.intCat=Category.intId) INNER JOIN tblcitylist ON
suppliers.intCity=tblcitylist.city_id) LEFT JOIN category AS category_1 ON
category.intParent=Category_1.intId
WHERE status='y';
我有三个表供应商,tblcitylist和类别。要获取具有intCat和intCity的供应商的数据,结果是具有城市名称(城市名称)和类别名称(strCategory)的供应商表的数据。
谢谢在这种情况下,使用直接SQL似乎更简单。更不用说它执行得更快了
$sql = "SELECT........";
$query = $this->db->query($sql);
这似乎是一种使用直接SQL更简单的情况。更不用说它执行得更快了
$sql = "SELECT........";
$query = $this->db->query($sql);
也许这就是你想要的
$query = $this->db->select('suppliers.*, category.strCategory, category_1.strCategory AS strParent, tblcitylist.city_name')
->from('suppliers')
->join('category', 'suppliers.intCat=Category.intId', 'inner')
->join('tblcitylist', 'suppliers.intCity=tblcitylist.city_id', 'inner')
->join('category as `category_1', 'category.intParent=Category_1.intId', 'left')
->where('status','y')
->get();
CI DB文档:也许这就是你想要的
$query = $this->db->select('suppliers.*, category.strCategory, category_1.strCategory AS strParent, tblcitylist.city_name')
->from('suppliers')
->join('category', 'suppliers.intCat=Category.intId', 'inner')
->join('tblcitylist', 'suppliers.intCity=tblcitylist.city_id', 'inner')
->join('category as `category_1', 'category.intParent=Category_1.intId', 'left')
->where('status','y')
->get();
CI DB文档: