Mysql 显示重复的行号

我将一个表连接到它本身以查找重复的行

select a.data, a.rowNumber, b.rowNumber
from DuplicateRows as a
join DuplicateRows as b 
on
a.data = b.data and a.Id != b.Id
group by a.data, a.rowNumber, b.rowNumber

此查询给出如下结果

"content" | 1 | 2
"content" | 1 | 6
"content" | 2 | 1
"content" | 2 | 6 
...and so on

为什么我要重写它以形成这样的结果

"content" | 1 | 2, 6

编辑

我认为这个问题应该纠正一下。 你看，我不想得到相反的结果，我的意思是我只想得到 一项

`1 -> 2, 6` 

不是

谢谢

使用组_CONCAT

---

尝试mysql中的GROUP_CONCAT函数

select a.data, a.rowNumber, group_concat(b.rowNumber)
from DuplicateRows as a
join DuplicateRows as b 
on
a.data = b.data and a.Id != b.Id
group by a.data, a.rowNumber, b.rowNumber

---

根据您最近的编辑，我认为这是您需要的：

SELECT a.data, a.a, GROUP_CONCAT( DISTINCT b.a)
FROM TableName as a
JOIN TableName as b 
    ON a.data = b.data AND a.a < b.a
GROUP BY a.data

附言 我用过并稍微修改了吴宇森的桌子

编辑 此查询的结果相对较好：

SELECT a.data, MIN(a.rowNumber), GROUP_CONCAT( DISTINCT b.rowNumber)
FROM DuplicateRows AS a
JOIN DuplicateRows AS b 
  ON a.data = b.data AND a.rowNumber < b.rowNumber
GROUP BY a.data

小提琴是。

而不是a.Id！=b、 我建议b.Id>a.Id

SELECT a.data, a.a, GROUP_CONCAT( DISTINCT b.a)
FROM TableName as a
JOIN TableName as b 
    ON a.data = b.data AND a.a < b.a
GROUP BY a.data

SELECT a.data, MIN(a.rowNumber), GROUP_CONCAT( DISTINCT b.rowNumber)
FROM DuplicateRows AS a
JOIN DuplicateRows AS b 
  ON a.data = b.data AND a.rowNumber < b.rowNumber
GROUP BY a.data