Mysql 按天列出的历史库存

我使用的是mysql，有一个记录库存订单的表。表（简化）如下所示：

||id|ordered_date |Date  |itemid| status    ||
||1 |Jan-4        |Jan-4 | a    | ordered   ||
||2 |Jan-6        |Jan-6 | b    | ordered   ||
||3 |Jan-8        |Jan-8 | c    | ordered   ||
||4 |Jan-8        |Jan-9 | c    | shipped   ||
||4 |Jan-6        |Jan-9 | b    | shipped   ||
||4 |Jan-4        |Jan-10| a    | shipped   ||

date  | inventory
Jan-4 |    1
Jan-5 |    1
Jan-6 |    2
Jan-7 |    2
Jan-8 |    3
Jan-9 |    1
Jan-10|    0

select count(*) from inventory where 
    status = "Shipped" AND 
    date > "Jan-8" AND 
    ordered_date <= "Jan-8"

我们想要的是每天尚未发货的订单总数，如下所示：

||id|ordered_date |Date  |itemid| status    ||
||1 |Jan-4        |Jan-4 | a    | ordered   ||
||2 |Jan-6        |Jan-6 | b    | ordered   ||
||3 |Jan-8        |Jan-8 | c    | ordered   ||
||4 |Jan-8        |Jan-9 | c    | shipped   ||
||4 |Jan-6        |Jan-9 | b    | shipped   ||
||4 |Jan-4        |Jan-10| a    | shipped   ||

date  | inventory
Jan-4 |    1
Jan-5 |    1
Jan-6 |    2
Jan-7 |    2
Jan-8 |    3
Jan-9 |    1
Jan-10|    0

select count(*) from inventory where 
    status = "Shipped" AND 
    date > "Jan-8" AND 
    ordered_date <= "Jan-8"

我可以使用以下查询查找任意一天未发货订单的总数：

||id|ordered_date |Date  |itemid| status    ||
||1 |Jan-4        |Jan-4 | a    | ordered   ||
||2 |Jan-6        |Jan-6 | b    | ordered   ||
||3 |Jan-8        |Jan-8 | c    | ordered   ||
||4 |Jan-8        |Jan-9 | c    | shipped   ||
||4 |Jan-6        |Jan-9 | b    | shipped   ||
||4 |Jan-4        |Jan-10| a    | shipped   ||

date  | inventory
Jan-4 |    1
Jan-5 |    1
Jan-6 |    2
Jan-7 |    2
Jan-8 |    3
Jan-9 |    1
Jan-10|    0

select count(*) from inventory where 
    status = "Shipped" AND 
    date > "Jan-8" AND 
    ordered_date <= "Jan-8"

从库存中选择盘点（*），其中
status=“Shipped”和
日期>“1月8日”和
订购日期尝试以下方法：

SELECT date, COUNT(*)
FROM inventory 
WHERE status != 'shipped'
GROUP BY date ORDER BY date;

真管用！比我想象的容易多了。我不知道我在想什么。谢谢