如何使用MySQL进行数据透视?
我有一个MySQL表: 我希望输出类似下面的内容(类似于旋转),Pen Pencil和Glue列中的值必须从最近的时间戳填充如何使用MySQL进行数据透视?,mysql,pivot,Mysql,Pivot,我有一个MySQL表: 我希望输出类似下面的内容(类似于旋转),Pen Pencil和Glue列中的值必须从最近的时间戳填充 您可以通过子查询的轴心来获得结果,该子查询标识每个类别-产品组的最新记录 SELECT t1.Category, MAX(CASE WHEN t1.Product = 'pen' THEN CONCAT(t1.Flag, '(productid-', t1.Product_ID, ')') ELSE NULL END) AS Pen,
您可以通过子查询的轴心来获得结果,该子查询标识每个
类别-产品组的最新记录
SELECT t1.Category,
MAX(CASE WHEN t1.Product = 'pen' THEN CONCAT(t1.Flag, '(productid-', t1.Product_ID, ')') ELSE NULL END) AS Pen,
MAX(CASE WHEN t1.Product = 'pencil' THEN CONCAT(t1.Flag, '(productid-', t1.Product_ID, ')') ELSE NULL END) AS Pencil,
MAX(CASE WHEN t1.Product = 'glue' THEN CONCAT(t1.Flag, '(productid-', t1.Product_ID, ')') ELSE NULL END) AS Glue
FROM yourTable t1
INNER JOIN
(
SELECT Category, Product, MAX(timestamp) AS timestamp
FROM yourTable
GROUP BY Category, Product
) t2
ON t1.Category = t2.Category AND
t1.Product = t2.Product AND
t1.timestamp = t2.timestamp
GROUP BY t1.Category
按照下面的链接进行运行演示:
您可以通过子查询的轴心来获得结果,该子查询标识每个类别-产品组的最新记录
SELECT t1.Category,
MAX(CASE WHEN t1.Product = 'pen' THEN CONCAT(t1.Flag, '(productid-', t1.Product_ID, ')') ELSE NULL END) AS Pen,
MAX(CASE WHEN t1.Product = 'pencil' THEN CONCAT(t1.Flag, '(productid-', t1.Product_ID, ')') ELSE NULL END) AS Pencil,
MAX(CASE WHEN t1.Product = 'glue' THEN CONCAT(t1.Flag, '(productid-', t1.Product_ID, ')') ELSE NULL END) AS Glue
FROM yourTable t1
INNER JOIN
(
SELECT Category, Product, MAX(timestamp) AS timestamp
FROM yourTable
GROUP BY Category, Product
) t2
ON t1.Category = t2.Category AND
t1.Product = t2.Product AND
t1.timestamp = t2.timestamp
GROUP BY t1.Category
按照下面的链接进行运行演示:
试试这个:
select
Category,
max(case when Product = 'pen' then concat(`Flag`, '(productid-', Product_ID, ')') else null end) as `Pen`,
max(case when Product = 'pencil' then concat(`Flag`, '(productid-', Product_ID, ')') else null end) as `Pencil`,
max(case when Product = 'glue' then concat(`Flag`, '(productid-', Product_ID, ')') else null end) as `Glue`
from (
select t1.*
from yourtable t1
join (
select Product, Category, max(`timestamp`) as `timestamp`
from yourtable
group by Product, Category
) t2 on t1.Product = t2.Product and t1.`timestamp` = t2.`timestamp` and t1.Category = t2.Category
) t
group by Category
试试这个:
select
Category,
max(case when Product = 'pen' then concat(`Flag`, '(productid-', Product_ID, ')') else null end) as `Pen`,
max(case when Product = 'pencil' then concat(`Flag`, '(productid-', Product_ID, ')') else null end) as `Pencil`,
max(case when Product = 'glue' then concat(`Flag`, '(productid-', Product_ID, ')') else null end) as `Glue`
from (
select t1.*
from yourtable t1
join (
select Product, Category, max(`timestamp`) as `timestamp`
from yourtable
group by Product, Category
) t2 on t1.Product = t2.Product and t1.`timestamp` = t2.`timestamp` and t1.Category = t2.Category
) t
group by Category
显示您尝试此查询的内容:从product_表中选择category、max(如果(product
='pen',flag,null))作为'pen',max(如果(product
='pen',flag,null))作为'Glue',这是给我的输出,但是,我不知道如何检索最新时间戳的标志值显示您尝试过的查询:选择类别,max(如果(product
='pen',flag,null))为'pen',max(如果(product
='pen',flag,null))为'Pencil',max(如果(product
='pen',flag,null))作为Product_表中的“Glue”,这给了我输出,但我不知道如何检索最新时间的标志值谢谢Tim…这对我很有效。你节省了我的时间谢谢Tim…这对我很有效。你节省了我的时间谢谢你的快速回复,这对我也很有效。非常感谢:)谢谢你的快速回复,这对我来说也很有效。非常感谢:)