Mysql 找到工资最低的公司

嗨，我有以下数据库scheema

employee (employee-name, street, city)
works (employee-name, company-name, salary)
company (company-name, city)
manages (employee-name, manager-name)

我需要找到工资最低的公司

SELECT company-name, sum(salary)
FROM works
GROUP BY company-name
ORDER BY sum(salary)

我写了以下问题，但我的培训师告诉我这是错误的

SELECT company-name
FROM works
GROUP BY company-name
HAVING sum(salary) < ( SELECT sum(salary)
FROM works
GROUP BY company-name)

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我再给你一个提示。您的子查询

SELECT company-name, sum(salary)
FROM works
GROUP BY company-name

将为您提供每家公司的累计工资。 如果您按升序排列这些数据，则第一条记录将是薪资最低的公司

SELECT company-name, sum(salary)
FROM works
GROUP BY company-name
ORDER BY sum(salary)

您可以使用MySQL的子句将该记录集限制为单个记录，使用

SELECT company-name, sum(salary)
FROM works
GROUP BY company-name
ORDER BY sum(salary)
LIMIT 1

在这种情况下，我们可以使用 e、 g:

SELECT company-name
FROM works
GROUP BY company-name
HAVING sum(salary) < ALL( SELECT sum(salary)
FROM works
GROUP BY company-name)

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不，我不支持在数据库上执行它，只要写一个像dat这样的查询，d Trainer就会告诉我它是否错误……子查询返回一家公司的工资总额。我是sql新手，所以没有太多的想法。。。