Mysql 从另一列sql/presto计算百分比
我有这张桌子Mysql 从另一列sql/presto计算百分比,mysql,sql,percentage,presto,Mysql,Sql,Percentage,Presto,我有这张桌子 month_year shopid payment_method count Jul-19 3lokpn99 CC 115 Jul-19 3lokpn99 PAYPALL 1 Jul-19 6jyhikmm CC 180 Jul-19 6jyhikmm PAYPALL 7 Aug-19 3lokpn99 CC 108
month_year shopid payment_method count
Jul-19 3lokpn99 CC 115
Jul-19 3lokpn99 PAYPALL 1
Jul-19 6jyhikmm CC 180
Jul-19 6jyhikmm PAYPALL 7
Aug-19 3lokpn99 CC 108
Aug-19 3lokpn99 PAYPALL 4
Aug-19 6jyhikmm CC 114
Aug-19 6jyhikmm PAYPALL 3
我要找的是计算每个月的付款方式的百分比。
期望的结果是这样的
month_year shopid payment_method count %
Jul-19 3lokpn99 CC 115 99.14
Jul-19 3lokpn99 PAYPALL 1 0.86
Jul-19 6jyhikmm CC 180 96.26
Jul-19 6jyhikmm PAYPALL 7 3.74
Aug-19 3lokpn99 CC 108 96.43
Aug-19 3lokpn99 PAYPALL 4 3.57
Aug-19 6jyhikmm CC 114 97.4
Aug-19 6jyhikmm PAYPALL 3 2.56
可能有不同的方法
- 使用窗口函数
- 带聚合的自连接(如Wojciech的回答中所示)
SELECT month_year, shopid, payment_method, count,
100e0 * count / sum(count) OVER (
PARTITION BY month_year, shopid
RANGE BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING)
AS "%"
FROM ...
(在Presto 318上测试)
请参阅Presto窗口函数文档
可能有不同的方法
- 使用窗口函数
- 带聚合的自连接(如Wojciech的回答中所示)
SELECT month_year, shopid, payment_method, count,
100e0 * count / sum(count) OVER (
PARTITION BY month_year, shopid
RANGE BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING)
AS "%"
FROM ...
(在Presto 318上测试)
请参阅Presto窗口函数文档
您可以通过查询获得此结果:
SELECT s.*, ROUND(s.count / ss.count_summed * 100,2) AS `%`
FROM stack s
JOIN (SELECT s.month_year, s.shopid, SUM(s.count) AS count_summed FROM stack s GROUP BY s.month_year, s.shopid) ss ON ss.month_year = s.month_year AND ss.shopid = s.shopid;
您可以通过查询来实现此结果:
SELECT s.*, ROUND(s.count / ss.count_summed * 100,2) AS `%`
FROM stack s
JOIN (SELECT s.month_year, s.shopid, SUM(s.count) AS count_summed FROM stack s GROUP BY s.month_year, s.shopid) ss ON ss.month_year = s.month_year AND ss.shopid = s.shopid;
thx人。但是,在运行查询之后。我想我需要从窗口函数中删除付款方法。它可以很好地工作,没有付款方式作为分区。再次感谢你再次帮助我。但是,在运行查询之后。我想我需要从窗口函数中删除付款方法。它可以很好地工作,没有付款方式作为分区。再次感谢你再次帮助我