MySQL从另一个表中选择前4名男性得分和前2名女性得分

我有一个MySQL查询问题，我感觉它需要连接表，但我对连接查询不是很有经验，我想知道是否有人能帮我

我有两张桌子。第一个被称为“大学”，看起来像这样：

id | name
 1 | University One
 2 | University Two

id | universityid | male | r1 | r2 | r3 | r4

我还有第二张表，叫做competitors，如下所示：

id | name
 1 | University One
 2 | University Two

id | universityid | male | r1 | r2 | r3 | r4

其中“universityid”是指第一个表的外键，“male”是决定竞争对手性别的布尔值，r1-r4是不同轮比赛的分数

所以这个表可能看起来像：

id | universityid | male | r1  | r2  | r3  | r4
-------------------------------------------------
 1 | 1            | 1    | 200 | 100 | 150 | 200
 2 | 1            | 1    | 50  | 100 | 150 | 200
 3 | 1            | 1    | 50  | 100 | 150 | 200
 4 | 1            | 1    | 50  | 100 | 150 | 200
 5 | 1            | 0    | 50  | 100 | 150 | 150
 6 | 1            | 0    | 50  | 100 | 150 | 150
 7 | 2            | 1    | 200 | 200 | 150 | 200
 8 | 2            | 1    | 200 | 100 | 150 | 200
 9 | 2            | 1    | 50  | 100 | 150 | 200
 10| 2            | 1    | 50  | 200 | 150 | 200
 11| 2            | 0    | 50  | 100 | 150 | 150
 12| 2            | 0    | 50  | 100 | 150 | 150

我想做的是找出每所大学每一轮（r1-r2）的前4名男性成绩和前2名女性成绩的总和，并返回每一轮的总数。然后将它们相加，得出每所大学所有轮的总分，然后根据这些总分按DESC顺序排列大学行

所以返回表可能是这样的

university.name | r1total | r2total | r3total | r4total | totalscore
---------------------------------------------------------------------
uni2name        | 600     | 800     | 900     | 1100    | 3400

uni1name        | 450     | 600     | 900     | 1100    | 3050

对此问题的任何帮助都将不胜感激

SELECT universityid,SUM(r1sum),SUM(r2sum),SUM(r3sum),SUM(r4sum),
SUM(r1sum+r2sum+r3sum+r4sum)as TotalScore 
FROM
(SELECT
 universityid,
CAST(SUBSTRING_INDEX(
   GROUP_CONCAT(r1 ORDER BY r1 DESC),
   ',', 1)as unsigned)+
 CAST(SUBSTRING_INDEX(SUBSTRING_INDEX(CONCAT(
   GROUP_CONCAT(r1 ORDER BY r1 DESC),',0'),
   ',', 2),',',-1)as unsigned)+
CAST(SUBSTRING_INDEX(SUBSTRING_INDEX(CONCAT(
   GROUP_CONCAT(r1 ORDER BY r1 DESC),',0'),
   ',', 3),',',-1)as unsigned)+
CAST(SUBSTRING_INDEX(SUBSTRING_INDEX(CONCAT(
   GROUP_CONCAT(r1 ORDER BY r1 DESC),',0'),
   ',', 4),',',-1)as unsigned)as r1sum,
 CAST(SUBSTRING_INDEX(
   GROUP_CONCAT(r2 ORDER BY r2 DESC),
   ',', 1)as unsigned)+
 CAST(SUBSTRING_INDEX(SUBSTRING_INDEX(CONCAT(
   GROUP_CONCAT(r2 ORDER BY r2 DESC),',0'),
   ',', 2),',',-1)as unsigned)+
CAST(SUBSTRING_INDEX(SUBSTRING_INDEX(CONCAT(
   GROUP_CONCAT(r2 ORDER BY r2 DESC),',0'),
   ',', 3),',',-1)as unsigned)+
CAST(SUBSTRING_INDEX(SUBSTRING_INDEX(CONCAT(
   GROUP_CONCAT(r2 ORDER BY r2 DESC),',0'),
   ',', 4),',',-1)as unsigned)as r2sum,
 CAST(SUBSTRING_INDEX(
   GROUP_CONCAT(r3 ORDER BY r3 DESC),
   ',', 1)as unsigned)+
 CAST(SUBSTRING_INDEX(SUBSTRING_INDEX(CONCAT(
   GROUP_CONCAT(r3 ORDER BY r3 DESC),',0'),
   ',', 2),',',-1)as unsigned)+
CAST(SUBSTRING_INDEX(SUBSTRING_INDEX(CONCAT(
   GROUP_CONCAT(r3 ORDER BY r3 DESC),',0'),
   ',', 3),',',-1)as unsigned)+
CAST(SUBSTRING_INDEX(SUBSTRING_INDEX(CONCAT(
   GROUP_CONCAT(r3 ORDER BY r3 DESC),',0'),
   ',', 4),',',-1)as unsigned)as r3sum,
  CAST(SUBSTRING_INDEX(
   GROUP_CONCAT(r4 ORDER BY r4 DESC),
   ',', 1)as unsigned)+
 CAST(SUBSTRING_INDEX(SUBSTRING_INDEX(CONCAT(
   GROUP_CONCAT(r4 ORDER BY r4 DESC),',0'),
   ',', 2),',',-1)as unsigned)+
CAST(SUBSTRING_INDEX(SUBSTRING_INDEX(CONCAT(
   GROUP_CONCAT(r4 ORDER BY r4 DESC),',0'),
   ',', 3),',',-1)as unsigned)+
CAST(SUBSTRING_INDEX(SUBSTRING_INDEX(CONCAT(
   GROUP_CONCAT(r4 ORDER BY r4 DESC),',0'),
   ',', 4),',',-1)as unsigned)as r4sum


FROM
 competitors
WHERE male=1
GROUP BY
 universityid
UNION ALL
SELECT
 universityid,
CAST(SUBSTRING_INDEX(
   GROUP_CONCAT(r1 ORDER BY r1 DESC),
   ',', 1)as unsigned)+
 CAST(SUBSTRING_INDEX(SUBSTRING_INDEX(CONCAT(
   GROUP_CONCAT(r1 ORDER BY r1 DESC),',0'),
   ',', 2),',',-1)as unsigned)as r1sum,
 CAST(SUBSTRING_INDEX(
   GROUP_CONCAT(r2 ORDER BY r2 DESC),
   ',', 1)as unsigned)+
 CAST(SUBSTRING_INDEX(SUBSTRING_INDEX(CONCAT(
   GROUP_CONCAT(r2 ORDER BY r2 DESC),',0'),
   ',', 2),',',-1)as unsigned)as r2sum,
  CAST(SUBSTRING_INDEX(
   GROUP_CONCAT(r3 ORDER BY r3 DESC),
   ',', 1)as unsigned)+
 CAST(SUBSTRING_INDEX(SUBSTRING_INDEX(CONCAT(
   GROUP_CONCAT(r3 ORDER BY r3 DESC),',0'),
   ',', 2),',',-1)as unsigned)as r3sum,
   CAST(SUBSTRING_INDEX(
   GROUP_CONCAT(r4 ORDER BY r4 DESC),
   ',', 1)as unsigned)+
 CAST(SUBSTRING_INDEX(SUBSTRING_INDEX(CONCAT(
   GROUP_CONCAT(r4 ORDER BY r4 DESC),',0'),
   ',', 2),',',-1)as unsigned)as r4sum
FROM
 competitors
WHERE male=0
GROUP BY
 universityid)x
GROUP BY universityid
ORDER BY TotalScore DESC

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每轮排名前4名的男性得分？显示一些样本数据或创建一个提琴。我已尝试编辑OP以使其更清晰。非常感谢您的帮助！这真是太棒了，除了如果某所大学在一轮比赛中没有进入一个完整的团队，那么它会重新计算分数。例如，如果一所大学在一轮比赛中只有一名男性参赛，那么它会将他的分数计算4次，而只需计算一次，其他分数则为0。有什么想法吗？对不起，我在OP中犯了另一个错误，我现在已经改正了。它应该返回大学的名称，而不是大学的id。我在我的电脑上试过了，最上面一行返回了大学名称中的所有0。第二行显示结果。。。但是，当我的测试数据中有三个UNI时，它也只显示太多行？？顺便说一句，谢谢你在这件事上的帮助！这就是我得到的。。。也许这与测试数据中有零有关…？@jamesmcillveen还将图像添加到表数据中