Mysql 如何计算django中这些条目的平均分数?
所以我有这个模型:Mysql 如何计算django中这些条目的平均分数?,mysql,django,django-forms,Mysql,Django,Django Forms,所以我有这个模型: class scoreShow(models.Model): dancer = models.ForeignKey(dancer) s1 = models.IntegerField(max_length = 2) s2 = models.IntegerField(max_length = 2) s3 = models.IntegerField(max_length = 2) s4 = models.IntegerField(max_le
class scoreShow(models.Model):
dancer = models.ForeignKey(dancer)
s1 = models.IntegerField(max_length = 2)
s2 = models.IntegerField(max_length = 2)
s3 = models.IntegerField(max_length = 2)
s4 = models.IntegerField(max_length = 2)
s5 = models.IntegerField(max_length = 2)
s6 = models.IntegerField(max_length = 2)
s7 = models.IntegerField(max_length = 2)
counter = models.IntegerField(max_length = 2)
stotal = models.IntegerField(max_length = 3)
field_1 = models.IntegerField(max_length = 20, null=True, blank=True)
field_2 = models.CharField(max_length = 20, null=True, blank=True)
def __unicode__(self):
return str(self.dancer)
从该视图表单中输入信息:
def scores(request):
perf = dancer.objects.filter(perform=True)
if request.method =='POST':
intpk = request.POST.get("form")
whendone = request.POST.get("done")
contestant =dancer.objects.get(pk=intpk)
showcase = inlineformset_factory(dancer, scoreShow, extra = 1)
form = showcase(instance=None)
if whendone == "save":
form = showcase(request.POST, request.FILES, instance=contestant)
if form.is_valid():
form.save()
return render_to_response("scores.html",locals(), context_instance = RequestContext(request))
它接受大约13个人的1到10的数值。我需要计算13个人的平均得分。2平均数:
from django.db.models import Avg
qs = ScoreShow.objects.all()
return qs.aggregate(Avg('s1'), Avg('s2'), Avg('s3'), Avg('s4'), Avg('s5'), Avg('s6'),Avg('s7'))
或者再短一点:
qs = ScoreShow.objects.all()
return qs.aggregate(*[Avg('s%d' % i) for i in range(1, 8)])
unique=True
:
class ScoreShow(models.Model):
dancer = models.ForeignKey(dancer, unique=True)
哇,谢谢,第一部分很好,但是对于总平均值,我一直得到这个错误:Sum'object没有属性'all',我用filter尝试过,我也得到了这个错误,有什么想法吗?再次感谢你我的错误,我忘记了一个结束括号。
class ScoreShow(models.Model):
dancer = models.ForeignKey(dancer, unique=True)