Mysql SQL-获取多个最接近的值

我想进行sql查询，搜索数据库以找到多个最接近的值 我有以下查询来查找最接近的值

SELECT * FROM table
WHERE price >= (50 * .9) and price <= (50 * 1.1)
order by abs(price - 50) LIMIT 1;

它工作正常，但我想让它搜索多个值，例如：

SELECT * FROM table
WHERE price >= (50 * .9) and price <= (50 * 1.1) //here i want one result (limit 1)
or price >= (50 * 1.9) and price <= (50 * 2.1) //here i want one result (limit 1)
order by abs(price - 50)

我想为每个价格限制1找不到所有的值。 我怎么能做到

//编辑 刚刚找到答案

(select *
  from table
  WHERE price >= (50 * .9) and price <= (50 * 1.1)
  order by abs(price - 50)
  limit 1
) union all
(select *
  from table
  WHERE price >= (50 * 1.9) and price <= (50 * 2.1)
  order by abs(price - 50)
  limit 1
)

使用union all怎么样

你想要这个吗

SELECT * FROM table
WHERE price >= (50 * .9) and price <= (50 * 1.1) //here i want one result    (limit 1)
 union
SELECT * FROM table
WHERE price >= (50 * 1.9) and price <= (50 * 2.1) //here i want one result  (limit 1)
 order by abs(price - 50)

---

ABSprice-2*50？是的，我刚在另一个网站上找到。无论如何，谢谢。因为您是按升序排序的，所以如果第一个查询不是空的，那么第二个查询将始终返回与第一个查询相同的结果。这使得第一个没用。

SELECT * FROM table
WHERE price >= (50 * .9) and price <= (50 * 1.1) //here i want one result    (limit 1)
 union
SELECT * FROM table
WHERE price >= (50 * 1.9) and price <= (50 * 2.1) //here i want one result  (limit 1)
 order by abs(price - 50)