Mysql 将结果分组到每小时存储桶的SQL查询

我有一个非常简单的MySQL表

Name  |  Time  |  Count
James |  11:00 |  10
Simon |  11:00 |  5
James |  11:30 |  4
Oliver|  11:30 |  2
James |  12:00 |  1
etc.

我想创建一个MySQL查询，对每个人的计数求和，并输出最后1小时值、最后3小时值、最后6小时值、最后12小时值和最后24小时值

e、 g.如果现在的时间是12:59，上表将输出：

Name  |  Last-1  |  Last-3  | Last-6
James |  1       |  15      | 15
Simon |  0       |  5       | 5
Oliver|  0       |  2       | 2

是否可以在单个查询中执行此操作？到目前为止，我已经：

SELECT name, HOUR( NOW( ) ) - HOUR( time ) AS lasthours, SUM( count ) AS c
FROM table
GROUP BY name, lasthours
HAVING lasthours =0
ORDER BY c DESC

这给了我过去的一个小时，但我如何获得额外的列

非常感谢您的帮助

编辑：

接受的答案需要稍加调整，结果如下：

SELECT  name , 
        SUM( IF( HOUR( TIMEDIFF( NOW( ) ,  time ) ) <=0,  count , 0 ) ) AS  `Last hour` ,
        SUM( IF( HOUR( TIMEDIFF( NOW( ) ,  time ) ) <=3,  count , 0 ) ) AS  `Last 3 hours` ,
        SUM( IF( HOUR( TIMEDIFF( NOW( ) ,  time ) ) <=6,  count , 0 ) ) AS  `Last 6 hours` ,
        SUM( IF( HOUR( TIMEDIFF( NOW( ) ,  time ) ) <=12,  count , 0 ) ) AS  `Last 12 hours` ,
        SUM( IF( HOUR( TIMEDIFF( NOW( ) ,  time ) ) <=24,  count , 0 ) ) AS  `Last 24 hours` ,
        SUM( IF( HOUR( TIMEDIFF( NOW( ) ,  time ) ) <=48,  count , 0 ) ) AS  `Last 2 days` ,
        SUM( IF( HOUR( TIMEDIFF( NOW( ) ,  time ) ) <=72,  count , 0 ) ) AS  `Last 3 days` ,
        SUM( IF( HOUR( TIMEDIFF( NOW( ) ,  time ) ) <=96,  count , 0 ) ) AS  `Last 4 days` ,
        SUM( IF( HOUR( TIMEDIFF( NOW( ) ,  time ) ) <=120,  count , 0 ) ) AS  `Last 5 days` ,
        SUM( IF( HOUR( TIMEDIFF( NOW( ) ,  time ) ) <=144,  count , 0 ) ) AS  `Last 6 days` ,
        SUM( IF( HOUR( TIMEDIFF( NOW( ) ,  time ) ) <=168,  count , 0 ) ) AS  `Last week`
FROM  table
GROUP BY  name
ORDER BY `Last hour` DESC

选择名称，
SUM（如果（HOUR（TIMEDIFF（NOW（），time））
选择'name'，
总和（如果（小时）（TIMEDIFF（CURTIME（），`Time`））
选择`name`，
SUM（如果（HOUR）（TIMEDIFF（CURTIME（），`Time`））试试这个

Select Name,Sum(Case When Hour(Now)-Hour(Time) <= 1 Then Count Else 0 End) As Last1,
Sum(Case When Hour(Now)-Hour(Time) Between 2 AND 3 Then Count Else 0 End) As Last3,
Sum(Case When Hour(Now)-Hour(Time) Between 4 And 6 Then Count Else 0 End) As Last6
From name
Order By 

选择Name，Sum（当小时（现在）-小时（时间）试试这个

Select Name,Sum(Case When Hour(Now)-Hour(Time) <= 1 Then Count Else 0 End) As Last1,
Sum(Case When Hour(Now)-Hour(Time) Between 2 AND 3 Then Count Else 0 End) As Last3,
Sum(Case When Hour(Now)-Hour(Time) Between 4 And 6 Then Count Else 0 End) As Last6
From name
Order By 

Select Name，Sum（Case When Hour（Now）-Hour（Time）稍作调整就可以了，但我更喜欢下面的解决方案。谢谢！稍作调整就可以了，但我更喜欢下面的解决方案。谢谢！这太棒了，谢谢。尽管我不得不将CURTIME（）改为Now（）这太棒了，谢谢。虽然我不得不把CURTIME（）改成NOW（）