Mysql 将SQL查询转换为具有多个表的sequelize查询

几天来，我一直在尝试将我认为相对简单的SQL查询转换为sequelize格式。我似乎一辈子也弄不明白。我对续集比较陌生，我的SQL技能也需要一些帮助

非常感谢您的帮助，谢谢

以下是我在sequelize中努力实现的SQL查询（它适用于我尝试执行的操作）：

    SELECT 
        book.id,
        book.author,
        book.title,
        book_type.type,
        book_sub_type.sub_type,
        book_location.location,
        book_language.language
    FROM book
    INNER JOIN book_type ON book.book_type_id = book_type.id
    INNER JOIN book_sub_type ON book.book_sub_type_id = book_sub_type.id
    INNER JOIN book_location ON book.book_location_id = book_location.id
    INNER JOIN book_language ON book.book_language_id = book_language.id
    WHERE
        book.author LIKE '%history%' OR
        book.title LIKE '%history%' OR
        book_type.type LIKE '%history%' OR
        book_sub_type.sub_type LIKE '%history%' OR
        book_language.language LIKE '%history%' OR
        book_location.location LIKE '%history%'
    ORDER BY book_type.type, book_sub_type.sub_type;

这是我所得到的（这个sequelize查询返回0个结果，因为它在所有列中搜索子字符串“history”，而不是至少一列）：

我的模式如下：

`book` table columns:
`id`, `author`, `title`, `book_type_id`, `book_sub_type_id`, 
`book_language_id`, `book_location_id`

`book_type` table columns:
`id`, `type`

`book_sub_type` table columns:
`id`, `sub_type`

`book_location` table columns:
`id`, `location`

`book_language` table columns:
`id`, `language`

在sequelize中，我建立了以下关系：

    Book.belongsTo(BookType);
    Book.belongsTo(BookSubType);
    Book.belongsTo(BookLanguage);
    Book.belongsTo(BookLocation);
    BookType.hasMany(Book);
    BookSubType.hasMany(Book);
    BookLanguage.hasMany(Book);
    BookLocation.hasMany(Book);

输出应为7列：

---

book.id、book.author、book.title、book_type.type、book_sub_type.sub_type、book_location.location、book_language.language

续集使用联接中的条件构建SQL，因此这不是一个好方法。您应该从includes中删除所有

where

条件。在续集中有一种方法谢谢你的回答，我担心我将不得不使用原始SQL来实现这一点。

    Book.belongsTo(BookType);
    Book.belongsTo(BookSubType);
    Book.belongsTo(BookLanguage);
    Book.belongsTo(BookLocation);
    BookType.hasMany(Book);
    BookSubType.hasMany(Book);
    BookLanguage.hasMany(Book);
    BookLocation.hasMany(Book);

 where: {
      $or: [{
        '$book.sub_type$$': 'history'
      }, {
        '$book_type.type$': 'history'
      }]
 } 

where: {
     [Op.or]: [{
         Sequelize.literal(`book_type.type LIKE ${history}`)
     }, {
         Sequelize.literal(`book_sub_type.sub_type LIKE ${history}`)
     }]
}