如何检索mysql中所有记录的树节点数？

我有一个mysql查询：

`select a.ID, a.parentID, a.name,
count(distinct b.ID) as level1,
count(distinct c.ID) as level2,
count(distinct d.ID) as level3,
count(distinct e.ID) as level4,
count(distinct f.ID) as level5,
count(distinct g.ID) as level6,
count(distinct h.ID) as level7,
count(distinct i.ID) as level8,
count(distinct j.ID) as level9,
count(distinct k.ID) as level10
from members a
left join members b on b.parentID = a.ID
left join members c on c.parentID = b.ID
left join members d on d.parentID = c.ID
left join members e on e.parentID = d.ID
left join members f on f.parentID = e.ID
left join members g on g.parentID = f.ID
left join members h on h.parentID = g.ID
left join members i on i.parentID = h.ID
left join members j on j.parentID = i.ID
left join members k on k.parentID = j.ID
left join members l on l.parentID = k.ID
where a.ID = 1`

我必须如何更新此查询以允许获取members表中的所有id，而不仅仅是检索一个查询结果。 我想替换a.ID=1的位置，例如：

`where a.id IN (select ID from members)`

问题是，当我这样做时，我只得到一行，所有计数都分组。我想在ID列表中获取级别列表

结果是：

`ID | parent | name        | lv1 | lv2 | lv3 | lb4 | lv5 | lv6 | lv7 | lv8 | lv9 | lv10 |`
`1  | 0      | Manish Shah | 3   | 9   | 27  | 81  | 36  | 0   | 0   | 0   | 0   | 0    |`

我想要

`ID | parent | name        | lv1 | lv2 | lv3 | lb4 | lv5 | lv6 | lv7 | lv8 | lv9 | lv10 |`
`1  | 0      | Manish Shah | 3   | 9   | 27  | 81  | 36  | 0   | 0   | 0   | 0   | 0    |`
`2  | 4      | luiset Shah | 3   | 9   | 27  | 81  | 36  | 0   | 0   | 0   | 0   | 0    |`
`3  | 8      | sarah kanna | 3   | 9   | 27  | 81  | 36  | 0   | 0   | 0   | 0   | 0    |`

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等等…

您需要对数据进行分组，即

WHERE a.id IN (2341,2342,2343,2344)
GROUP BY a.id

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如果您想要所有成员，只需删除

WHERE

子句，但您需要一个

按a.ID分组

有一个名为introID的额外字段，它是向程序引入另一个成员的成员的ID，那么，如何获得每个级别的introID总数？@LuisParada有什么区别？我的意思是，你可以在任何领域做不同的计数。。。如果是另一个问题，请在单独的问题中提问。