如何获取MySQL的结果：[从mytable中选择*作为t]？

我有这样一个SQL：

SELECT m1.id1,m2.user,m3.pass,m4.cap,m5.test
FROM
(SELECT * FROM mytable) AS m1,
(SELECT * FROM mytable) AS m2,
(SELECT * FROM mytable) AS m3,
(SELECT * FROM mytable) AS m4,
(SELECT * FROM mytable) AS m5
WHERE m1.id1=m2.id2 AND m1.id1=m3.id3 AND m1.id1=m4.id4 AND m1.id1=m5.id5;

表mytable很大，但我需要从中获取所有信息，并且我需要多次使用子查询，问题是：如何从mytable保存querySELECT*的结果，如：

SELECT m1.id1,m2.user,m3.pass,m4.cap,m5.test
FROM
(SELECT * FROM mytable) AS m1,
m1 AS m2,
m1 AS m3,
m1 AS m4,
m1 AS m5
WHERE m1.id1=m2.id2 AND m1.id1=m3.id3 AND m1.id1=m4.id4 AND m1.id1=m5.id5;

非常感谢。

您应该使用加入：

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正确的方法是使用JOIN并让优化器完成其工作：

SELECT m1.id1,m2.user,m3.pass,m4.cap,m5.test
  FROM mytable as m1
  JOIN mytable as m2 ON m1.id1=m2.id2
  JOIN mytable as m3 ON m1.id1=m3.id3
  JOIN mytable as m4 ON m1.id1=m4.id4
  JOIN mytable as m5 ON m1.id1=m5.id5 ;

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使用子查询从表中选择所有数据是没有意义的…

您是科罗拉多州最快的！

SELECT m1.id1,m2.user,m3.pass,m4.cap,m5.test
  FROM mytable as m1
  JOIN mytable as m2 ON m1.id1=m2.id2
  JOIN mytable as m3 ON m1.id1=m3.id3
  JOIN mytable as m4 ON m1.id1=m4.id4
  JOIN mytable as m5 ON m1.id1=m5.id5 ;