MySQL查找第一次未购买的客户的交易（付款）

我有一个简单的表，里面有交易，我想得到，每个月，有多少消费者的交易总数超过0，而他们的第一笔交易不是在那个月。我们所说的第一笔交易是指客户在该月内首次购买

我试图得到的结果如下：

+--------+---------+-----------------------------------+
|  Year  |  Month  |  NumOfCustomersWithPositiveTotals |
+--------+----------------------------+----------------+
|  2014  |    1    |                 22                |
+--------+----------------------------+----------------+
|  2014  |    2    |                 10                |
+--------+----------------------------+----------------+

我有一个SQL小提琴，我发现同样的事情，但消费者有他们的第一笔交易在该月内。实际上，我正在寻找的查询是相同的，但对于其他消费者来说是一样的

---

这是小提琴：

我想这就是你想要的：

SELECT count(consumerId) as NumOfCust, mm, yy FROM
(
    SELECT consumerId, month(date) as mm, year(date) as yy, sum(amount) as total, mdate FROM beta.transaction as t
    LEFT JOIN (
            SELECT min(month(date)) as mdate, consumerId as con FROM beta.transaction
            GROUP BY consumerId
            ) as MinDate ON con = t.consumerId
    GROUP BY month(date), consumerId
    HAVING mdate < mm AND total > 0
) as res
GROUP BY res.mm;

下一个

最后，通过外部选择，我们按月对上述结果进行分组统计。

---

我希望这是您想要的。

下面的查询返回正确的结果。答案基于Akis的答案，在GROUPBY子句中添加consumerId，并在支票中添加年份和月份

select
    tyyyy, tmm, count(tcon) as oldkund_real
from
(
    select
        t.yyyy as tyyyy, t.mm as tmm, t.consumerId as tcon, sum(t.amount) as total, fp.yyyy as fpyyyy, fp.mm as fpmm, fp.consumerId as fpcon
    from
        (
            select
                year(date) as yyyy, month(date) as mm, consumerId, amount
            from
                transaction
        ) as t
        left join
        (
            select
                year(min(date)) as yyyy, month(min(date)) as mm, consumerId
            from
                transaction
            group by
                consumerid
        ) as fp
        on
            t.consumerId = fp.consumerId
        group by
            t.yyyy, t.mm, t.consumerId
        having
            STR_TO_DATE(CONCAT('01,', tmm, ',', tyyyy),'%d,%m,%Y') > STR_TO_DATE(CONCAT('01,', fpmm, ',', fpyyyy),'%d,%m,%Y') and total > 0
) as res
group by
    tyyyy, tmm
order by
    tyyyy, tmm;

---

非常感谢阿基斯

非常感谢您的回复！我对你的问题做了一点修改，我在下面贴了一个答案，这正是我所需要的。

SELECT consumerId, month(date) as mm, year(date) as yy, sum(amount), mdate FROM beta.transaction as t
    LEFT JOIN (
            SELECT min(month(date)) as mdate, consumerId as con FROM beta.transaction
            GROUP BY consumerId
            ) as MinDate ON con = t.consumerId
    GROUP BY month(date), consumerId
    HAVING mdate < mm AND total > 0

 -- Here we find total amount per consumerId per month and count only the consumers whose first transact (aka minDate) is lower than current month AND total is greater than 0

select
    tyyyy, tmm, count(tcon) as oldkund_real
from
(
    select
        t.yyyy as tyyyy, t.mm as tmm, t.consumerId as tcon, sum(t.amount) as total, fp.yyyy as fpyyyy, fp.mm as fpmm, fp.consumerId as fpcon
    from
        (
            select
                year(date) as yyyy, month(date) as mm, consumerId, amount
            from
                transaction
        ) as t
        left join
        (
            select
                year(min(date)) as yyyy, month(min(date)) as mm, consumerId
            from
                transaction
            group by
                consumerid
        ) as fp
        on
            t.consumerId = fp.consumerId
        group by
            t.yyyy, t.mm, t.consumerId
        having
            STR_TO_DATE(CONCAT('01,', tmm, ',', tyyyy),'%d,%m,%Y') > STR_TO_DATE(CONCAT('01,', fpmm, ',', fpyyyy),'%d,%m,%Y') and total > 0
) as res
group by
    tyyyy, tmm
order by
    tyyyy, tmm;