具有多个值的MySQL更新查询

我在数据库中有一个表，其中包含以下记录：

match_id | guess | result
   125   |   1   |   0
   130   |   5   |   0
   233   |   11  |   0
   125   |   2   |   0

UPDATE `tahminler` SET result=1 WHERE match_id='1640482' AND tahmin='8'
UPDATE `tahminler` SET result=1 WHERE match_id='1640482' AND tahmin='11'
UPDATE `tahminler` SET result=0 WHERE match_id='1640482' AND tahmin='1'
UPDATE `tahminler` SET result=0 WHERE match_id='1640482' AND tahmin='2'
UPDATE `tahminler` SET result=0 WHERE match_id='1640482' AND tahmin='3'
UPDATE `tahminler` SET result=0 WHERE match_id='1640482' AND tahmin='4'
UPDATE `tahminler` SET result=0 WHERE match_id='1640482' AND tahmin='5'
UPDATE `tahminler` SET result=0 WHERE match_id='1640482' AND tahmin='6'
UPDATE `tahminler` SET result=0 WHERE match_id='1640482' AND tahmin='7'
UPDATE `tahminler` SET result=0 WHERE match_id='1640482' AND tahmin='9'
UPDATE `tahminler` SET result=0 WHERE match_id='1640482' AND tahmin='10'

我的用户为每个匹配选择一个猜测，我有一个函数，根据匹配结果计算猜测结果： 如果猜测正确，结果将是（1） 如果错误，结果将是（2） 如果匹配尚未完成，结果将为（0默认值） 我有十一种猜测的可能性（不止一种可能同时是正确的） 例如：如果我有一个id=125的匹配项，并且我所有的猜测都错了，除了8,11 因此，我应该更新所有匹配项的结果字段，这些匹配项具有匹配id，并且它们的猜测值为8或11（对于这个结果字段，我将给出1） 对于同一场比赛的其他猜测，我想给出（2）

我将此查询用于以下十一种可能性：

match_id | guess | result
   125   |   1   |   0
   130   |   5   |   0
   233   |   11  |   0
   125   |   2   |   0

UPDATE `tahminler` SET result=1 WHERE match_id='1640482' AND tahmin='8'
UPDATE `tahminler` SET result=1 WHERE match_id='1640482' AND tahmin='11'
UPDATE `tahminler` SET result=0 WHERE match_id='1640482' AND tahmin='1'
UPDATE `tahminler` SET result=0 WHERE match_id='1640482' AND tahmin='2'
UPDATE `tahminler` SET result=0 WHERE match_id='1640482' AND tahmin='3'
UPDATE `tahminler` SET result=0 WHERE match_id='1640482' AND tahmin='4'
UPDATE `tahminler` SET result=0 WHERE match_id='1640482' AND tahmin='5'
UPDATE `tahminler` SET result=0 WHERE match_id='1640482' AND tahmin='6'
UPDATE `tahminler` SET result=0 WHERE match_id='1640482' AND tahmin='7'
UPDATE `tahminler` SET result=0 WHERE match_id='1640482' AND tahmin='9'
UPDATE `tahminler` SET result=0 WHERE match_id='1640482' AND tahmin='10'

我想知道我是否可以在一个查询中完成这项工作？

使用以下两个查询：

UPDATE `tahminler` 
        SET result=0 
        WHERE match_id='1640482' 
              AND tahmin IN ('1','2','3','4','5','6','7','9','10')

然后用这个：

UPDATE `tahminler` 
        SET result=1 
        WHERE match_id='1640482' 
              AND tahmin IN ('8','11')

---

你可以这样做，但也会很难看。使用运算符，如：

UPDATE tahminler
SET
  result=CASE
    WHEN tahmin IN ('1','2','3','4','5','6','7','8','9','10') THEN 0
    WHEN tahmin IN ('8', 11) THEN 1
  END
WHERE
  match_id='1640482'

---

我认为这是更可取的选择。。我喜欢只有一个语句而不是多个语句