合并重复的电子邮件和点mysql

我有一个MySQL表，它有三列：

Userid         | Email               | Points
---------------------------------------------------------
1              | jdoe@company.com    | 20
2              | jdoe%40company.com  | 25
3              | rwhite@company.com  | 14
4              | rwhite%40company.com| 10

我想做的是删除重复的电子邮件和合并点。我希望我的桌子看起来像这样：

Userid         | Email               | Points
---------------------------------------------------------
1              | jdoe@company.com    | 45
3              | rwhite@company.com  | 24

我的查询如何返回我的愿望表

有人知道怎么做吗

---

提前谢谢

你在找这样的东西吗

SELECT MIN(userid) userid, email, SUM(points) points
  FROM 
(
  SELECT userid, REPLACE(email, '%40', '@') email, points
    FROM table1
) q
  GROUP BY email

输出：

| USERID | EMAIL | POINTS | |--------|--------------------|--------| | 1 | jdoe@company.com | 45 | | 3 | rwhite@company.com | 24 | 这是演示

现在，如果要就地消除表中的重复数据，可以执行以下操作

-- Fix emails
UPDATE table1
   SET email = REPLACE(email, '%40', '@')
 WHERE email LIKE '%\%40%';
-- Merge points for duplicate records
UPDATE table1 t JOIN
(
  SELECT email, SUM(points) points
    FROM table1
   GROUP BY email
  HAVING COUNT(*) > 1
) q ON t.email = q.email
   SET t.points = q.points;
-- Delete all duplicate records except ones with lowest `userid`
DELETE t 
  FROM table1 t JOIN
(
  SELECT MIN(userid) userid, email
    FROM table1
   GROUP BY email
  HAVING COUNT(*) > 1
) q ON t.email = q.email
 WHERE t.userid <> q.userid;

---

这里是演示

假设您希望在不进行任何修改的情况下按原样匹配电子邮件，则使用此查询

SELECT MIN(user_id), SUM(points)as points, email FROM table_name GROUP BY email

---

@AndyMartin有帮助吗？