查找最接近的值-MySQL

如何为多个值找到最接近的值

例如： 我有这张桌子

A 1

B 2

C 3

D 7

E 11

F 12

所以-

谢谢

试试这个：

SELECT t1.col1, t2.col1
FROM mytable AS t1
INNER JOIN mytable AS t2 
  ON t1.col1 <> t2.col1
LEFT JOIN mytable AS t3 
  ON t3.col1 <> t2.col1 AND t3.col1 <> t1.col1 AND 
     ABS(t3.col2 - t1.col2) < ABS(t2.col2 - t1.col2)
WHERE t3.col1 IS NULL  
ORDER BY t1.col1

试试这个：

SELECT t1.col1, t2.col1
FROM mytable AS t1
INNER JOIN mytable AS t2 
  ON t1.col1 <> t2.col1
LEFT JOIN mytable AS t3 
  ON t3.col1 <> t2.col1 AND t3.col1 <> t1.col1 AND 
     ABS(t3.col2 - t1.col2) < ABS(t2.col2 - t1.col2)
WHERE t3.col1 IS NULL  
ORDER BY t1.col1

---

你可以用这样的小翻译表

CREATE TABLE `translate` (
  `id` int(11) unsigned NOT NULL AUTO_INCREMENT,
  `from` char(1) DEFAULT NULL,
  `to` char(1) DEFAULT NULL,
  PRIMARY KEY (`id`),
  KEY `from` (`from`)
) ENGINE=InnoDB AUTO_INCREMENT=8 DEFAULT CHARSET=utf8;

INSERT INTO `translate` (`id`, `from`, `to`)
VALUES
    (1, 'A', 'B'),
    (2, 'B', 'A'),
    (3, 'B', 'C'),
    (4, 'C', 'B'),
    (5, 'D', 'E'),
    (6, 'E', 'F'),
    (7, 'F', 'E');

样品

---

你可以用这样的小翻译表

CREATE TABLE `translate` (
  `id` int(11) unsigned NOT NULL AUTO_INCREMENT,
  `from` char(1) DEFAULT NULL,
  `to` char(1) DEFAULT NULL,
  PRIMARY KEY (`id`),
  KEY `from` (`from`)
) ENGINE=InnoDB AUTO_INCREMENT=8 DEFAULT CHARSET=utf8;

INSERT INTO `translate` (`id`, `from`, `to`)
VALUES
    (1, 'A', 'B'),
    (2, 'B', 'A'),
    (3, 'B', 'C'),
    (4, 'C', 'B'),
    (5, 'D', 'E'),
    (6, 'E', 'F'),
    (7, 'F', 'E');

样品

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