Mysql 使用“选择结果”生成表格

我有一张这样的桌子：

我要执行以下SELECT语句：

SELECT count(*) from table WHERE A=1 and date between 2013-02 and 2013-03
SELECT count(*) from table WHERE A=1 and date between 2013-03 and 2013-04
SELECT count(*) from table WHERE A=1 and date between 2013-04 and 2013-05
....
SELECT count(*) from table WHERE B=1 and date between 2013-02 and 2013-03
SELECT count(*) from table WHERE B=1 and date between 2013-03 and 2013-04
SELECT count(*) from table WHERE B=1 and date between 2013-04 and 2013-05
...etc

最快的查询是什么？我可以将结果安排在如下表格中：

date    |A=1  |B=1  |C=1  |...
2013-Feb|count|count|count|
2013-Mar|count|...

如果列

A

到

E

中的值仅为0或1（或可能

NULL

），则我们可以简化为：

SELECT DATE_FORMAT(date, '%Y-%m'),
       SUM(A) AS Acount,
       SUM(B) AS Bcount,
       SUM(C) AS Ccount,
       SUM(D) AS Dcount,
       SUM(E) AS Ecount
FROM table
GROUP BY DATE_FORMAT(date, '%Y-%m')

---

您好，
您可以使用分组方式功能

    SELECT 
    to_char(date,'YYYY-MM') as date,
    CASE WHEN A=1 THEN COUNT(A)  END as A ,
    CASE WHEN B=1 THEN COUNT(B)  END as B ,
    CASE WHEN C=1 THEN COUNT(C)  END as C ,
    CASE WHEN D=1 THEN COUNT(D)  END as D ,
    CASE WHEN E=1 THEN COUNT(E)  END as E  
    from table_name group by date order by date

---

此查询根据年份和月份对列进行分组，并提供结果

从日期提取月份并按月份进行分组。最后计数。这是一个透视表，有关解决方案的示例，请参见

    SELECT 
    to_char(date,'YYYY-MM') as date,
    CASE WHEN A=1 THEN COUNT(A)  END as A ,
    CASE WHEN B=1 THEN COUNT(B)  END as B ,
    CASE WHEN C=1 THEN COUNT(C)  END as C ,
    CASE WHEN D=1 THEN COUNT(D)  END as D ,
    CASE WHEN E=1 THEN COUNT(E)  END as E  
    from table_name group by date order by date