Mysql 跨多个表选择不同的查询

我有一个名字，姓氏，电子邮件，前_姓的用户模型。还有一种额外的电子邮件模型，我在其中为用户存储额外的电子邮件。每个用户可以有多封额外的电子邮件。在每个模型中分别存在hasMany和BelongMathany集的关系。 我必须搜索姓氏、以前的姓氏、电子邮件和其他电子邮件。我尝试使用containable行为，并为查询创建了下表：

$options['joins'] = array(
    array(
        'table' => 'users',
        'alias' => 'User',
        'type' => 'LEFT',
        'conditions' => array('User.id = AdditionalEmail.user_id')
    ));
$options['conditions'] = array('OR' => array(
    'User.surname LIKE' => $search,
    'User.former_surnames LIKE' => $search,
    'User.email LIKE' => $search,
    'AdditionalEmail.email LIKE' => $search));
$options['recursive'] = -1;
$options['fields'] = 'DISTINCT User.username, User.name, User.surname, User.former_surnames';
$options['order'] = array('User.surname' => 'asc');

然而，上述情况对我不起作用。最后我提出了一个问题：

SELECT DISTINCT users.* FROM users LEFT JOIN additional_emails ON ( users.id = additional_emails.user_id ) WHERE ((additional_emails.email LIKE  \''. $search .'\') OR (users.email LIKE \''. $search .'\') OR (users.surname LIKE \''. $search .'\') OR (users.former_surnames LIKE \''. $search .'\')) ORDER BY users.surname

哪个好用。如何使用cakephp选项为find（或paginate）构建此查询。 当做 皮奥特

 $this->User->find('all', 
     array(
         'fields' => array('DISTINCT *'), 
         'joins' => array(
               array(
                    'table' => 'additional_emails',
                    'alias' => 'Email',
                    'type' => 'left',
                    'conditions' => array('User.id = Email.user_id')
               ),
          ),
          'conditions' => array(
               'OR' => array(
                   'Email.email LIKE' => $search,
                   'User.email LIKE' => $search,
                   'User.surname LIKE' => $search,
                   'User.former_surnames LIKE' => $search,
                )
          ),
          'order' => array('User.surname'),
     )
 );