Mysql 如何使用条件乘法编写sql语句?
假设我有一张如下表: 时间表Mysql 如何使用条件乘法编写sql语句?,mysql,sql,Mysql,Sql,假设我有一张如下表: 时间表 +-------+------------+--------+----------------+-------+---------+ | index | date | empid | dept | sfrom | slength | +-------+------------+--------+----------------+-------+---------+ | 0 | 09-24-2018 | 943023 | RA
+-------+------------+--------+----------------+-------+---------+
| index | date | empid | dept | sfrom | slength |
+-------+------------+--------+----------------+-------+---------+
| 0 | 09-24-2018 | 943023 | RADIOLOGY | 03PM | 8 |
| 1 | 09-24-2018 | 891046 | SURGERY | 07AM | 8 |
| 2 | 09-24-2018 | 878397 | RADIOLOGY | 11PM | 8 |
| 3 | 09-24-2018 | 886190 | CARDIOLOGY | 03PM | 8 |
| 4 | 09-24-2018 | 878397 | RADIOLOGY | 11PM | 8 |
| 5 | 09-24-2018 | 891330 | SURGERY | 03PM | 8 |
| 6 | 09-24-2018 | 995561 | SURGERY | 11PM | 8 |
| 7 | 09-24-2018 | 967577 | MATERNITY | 03PM | 8 |
| 8 | 09-24-2018 | 913891 | PEDIATRICS | 03PM | 8 |
| 9 | 09-24-2018 | 939148 | EMERGENCY | 07AM | 8 |
| 10 | 09-24-2018 | 995636 | RADIOLOGY | 11PM | 8 |
| 11 | 09-24-2018 | 995561 | EMERGENCY | 11PM | 8 |
| 12 | 09-24-2018 | 967577 | SURGERY | 07AM | 8 |
| 13 | 09-24-2018 | 883069 | INTENSIVE CARE | 07AM | 8 |
| 14 | 09-24-2018 | 951876 | ONCOLOGY | 03PM | 8 |
| 15 | 09-24-2018 | 884866 | CARDIOLOGY | 07AM | 8 |
| 16 | 09-24-2018 | 864425 | ONCOLOGY | 03PM | 8 |
员工表
+-------+--------+------------+-----------+---------+----------------+----------------+------+
| index | empid | lastName | firstName | emptype | cellphone | homephone | ftpt |
+-------+--------+------------+-----------+---------+----------------+----------------+------+
| 0 | 919675 | Cermak | Vern | LPN | (138)7198-0862 | (655)2249-9926 | FT |
| 1 | 906704 | Paille | Lorilee | NULL | (858)1100-2722 | (377)1506-1986 | PT |
| 2 | 900486 | Ober | Shalanda | NULL | (210)1508-8132 | (820)1612-0197 | FT |
| 3 | 883367 | Clyburn | Jeffry | LPN | (420)7798-7220 | (476)7661-3070 | FT |
| 4 | 953807 | Quarles | Timmy | LPN | (513)2756-9892
如果我必须计算每个部门、每个员工类型和每个班次的总成本,我应该如何在sql中进行计算
如果班次包括午夜,我的工资乘以25%
我有如下示例输出,但不知道如何执行此操作:
+------------+---------------+----------------+---------+
| DEPARTMENT | EMPLOYEE_TYPE | SHIFT | COST |
+------------+---------------+----------------+---------+
| Anesthesia | LPN | 7 AM –3 | $24,567 |
| Anesthesia | LPN | 3 PM –11PM | $18,546 |
| Anesthesia | LPN | 11 PM –7AM | $22,874 |
| Anesthesia | NA | 7 AM –3 PM | $9,764 |
| Anesthesia | NA | 3 PM –11 PM | $10,287 |
| Anesthesia | NA | 11 PM –7 AM | $6, 875 |
| Anesthesia | RN | 7 AM –3 PM | $33,123 |
+------------+---------------+----------------+---------+
这是我迄今为止的sql语句:
但是我该如何让它工作呢?
编辑1:
编辑2:
Select
t1.dept,
t2.emptype,
t1.sfrom,
t1.slength,
SUM(t1.slength) as hours
CASE WHEN HOUR(STR_TO_DATE(sfrom,'%h%p') +
STR_TO_DATE(slength,'%H')) > 23
then (slength*10*1.25) else (slength*10)
from
schedule_2 as t1
Join (select
empid,
emptype
from`
employees_2) as t2 ON t1.empid=t2.empid
GROUP BY
dept,
emptype,
slength;
我得到以下错误,但似乎无法找出原因
您的SQL语法有错误;检查手册
对应于要使用的正确语法的MariaDB服务器版本
接近“时长时长”的情况(STR_至_日期(从,%h%p'开始)+
STR_TO_DATE(长度,'%H'))>23,然后在第2行
您可以在sql语句中为成本字段使用case子句。例如:
case when <<your clause for night shift>> then (slength*10)+(0.25*10*slength)
else (slength*10) end as cost
当时的情况(长度*10)+(0.25*10*长度)
其他(长度*10)作为成本结束
假设是每小时10美元。您可以根据您的业务规则设置夜班条件。到目前为止,您是否已设置夜班条件?是的,我正在尝试将两个表连接在一起,然后进行分组,但仍然无法执行。我是sql的新手:/你能不能也包括你的查询?工资或每小时的价格在哪里?我在任何表格上都看不到……您只是在
案例中漏掉了附近的逗号。。当进行查询时,请使您的查询可读。。它将帮助您查找输入错误或丢失。。当然,美观。如果转换时间是字符串列,你能显示整个SQL查询吗?你考虑什么时间午夜?第二,轮班是否每小时开始,如凌晨1点、凌晨2点等?凌晨12点是午夜时间,轮班可以在任何时候开始,但如果在凌晨12点或更晚时间结束,则成本为1.2倍。在总和(t1.slength)后加逗号(,),如下所示:hours@Ryan在顶部查看我的评论并接受我的评论。。当您有可读的查询时,将更容易看到。。
case when <<your clause for night shift>> then (slength*10)+(0.25*10*slength)
else (slength*10) end as cost