MySql多选一行

我不知道如何从表中获取行：

我在一个范围/条件中搜索，需要7列：最大价格、最小价格、最后价格、如果和何时价格>=x，因此第一个价格>=x及其时间，如果和何时价格将单词放在每个join语句的前面

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这样做表明查询应该返回第一个表中的所有行，而不管它是否在第二个表中找到匹配的行。

感谢您的回答，我刚刚在每个表的前面添加了左行，但返回了一个1064语法错误。。。对不起，我不是专家。。。

id (int, key unique)
date (varchar, don't need it) 
price (decimal) 
unix (int, key) (unix time)
ck (int, key)
fk (int, key)

SELECT *  FROM 
    (SELECT date , price as 'Sprc', unix as 'Sunx' 
    FROM prices WHERE
        (unix BETWEEN 1420185600 AND 1420192800) AND
        ck>0 AND fk=0 AND 
        price <= 1000 
    order by unix ASC limit 1) as tmp1
JOIN
    (SELECT date , price as 'TPprc', unix as 'TPunx'  
    FROM prices WHERE  
        (unix BETWEEN 1420185600 AND 1420192800) AND  
        ck>0 AND 
        fk=0 AND 
        price >= 100 
    order by unix ASC limit 1) as tmp2
JOIN
    (SELECT MIN(price) as 'min', MAX(price) as 'max'  
    FROM prices WHERE 
        ck>0 AND 
        fk=0 AND  
        (unix BETWEEN 1420185600 AND 1420192800) 
    order by unix ASC limit 1)  as tmp3
JOIN
    (SELECT date, price as 'last'  
    FROM prices WHERE 
        ck>0 AND 
        fk=0 AND 
        (unix BETWEEN 1420185600 AND 1420192800) 
    order by unix DESC limit 1)  as tmp4;