如何直接从MySQL查询中获取两个总和的百分比？

我正在使用此查询计算数据库中男性和女性的百分比：

SELECT sum(case when `gender` = 'M' then 1 else 0 end) as male
     , sum(case when `gender` = 'F' then 1 else 0 end) as female
FROM userinfo 
WHERE id in (10,1,5)

然后在php中计算百分比。但我想知道，有没有办法直接从查询中获取百分比

SELECT sum(case when `gender` = 'M' then 1 else 0 end) as male
     , 100*sum(case when `gender` = 'M' then 1 else 0 end)/count(*) as malepct
     , sum(case when `gender` = 'F' then 1 else 0 end) as female
     , 100*sum(case when `gender` = 'F' then 1 else 0 end)/count(*) as femalepct
FROM userinfo 
WHERE id in (10,1,5)

。。。假设不在空行集上运行此操作（除零）

例如，如果您希望将无效（除零）值替换为-1，请使用

if(ifnull(count(*),0)>0,100*sum(case when `gender` = 'M' then 1 else 0 end)/count(*),-1) as malepct

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有没有办法在计算前检查以避免div为零？