是否基于mysql中状态列的最小编号更新列？

我想用状态=8更新数字2

UPDATE tqueue 
SET status = '8' 
WHERE (SELECT MIN(number) 
       FROM tqueue
       WHERE STATUS IN ('4')
         AND get_ticket >= CURDATE( ) 
         AND get_ticket < DATE_ADD( CURDATE(), INTERVAL 1 DAY) 
       GROUP BY service)

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您是否希望将状态为8的最小编号更新为状态为4

试试这个：

 SELECT @mynumber:=number FROM tqueue
 WHERE STATUS = '4'
 AND get_ticket >= CURDATE( )
 AND get_ticket < DATE_ADD( CURDATE() , INTERVAL 1 DAY )
 GROUP BY service
 order by number asc
 limit 0,1 ;

 UPDATE tqueue SET status = '8' where number = @mynumber ;

此外，您还可以使用临时表进行更新自引用：

 CREATE TEMPORARY TABLE mytbl_numbers AS 
 SELECT number FROM tqueue
 WHERE STATUS = '4'
 AND get_ticket >= CURDATE( )
 AND get_ticket < DATE_ADD( CURDATE() , INTERVAL 1 DAY )
 GROUP BY service
 order by number asc
 limit 0,1 ;

 UPDATE tqueue SET status = '8' where number in (SELECT * FROM  mytbl_numbers) ;

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更多有用的答案可以在&&…

更新tqueue set status=8，其中number=2。请解释这是否解决了您的问题，或者为什么不以一致的wya更新您的问题。。您引用的列和条件不在您的示例和解释中..当我每次更新数据时，状态为4的min编号将更改为状态8，不仅是编号2，它的错误为1093-您不能为我的错误指定从子句中更新的目标表'tqueue'，在更新和删除中，目标表和源表不能使用一个表。所以我改变了代码，它解决了吗？

 CREATE TEMPORARY TABLE mytbl_numbers AS 
 SELECT number FROM tqueue
 WHERE STATUS = '4'
 AND get_ticket >= CURDATE( )
 AND get_ticket < DATE_ADD( CURDATE() , INTERVAL 1 DAY )
 GROUP BY service
 order by number asc
 limit 0,1 ;

 UPDATE tqueue SET status = '8' where number in (SELECT * FROM  mytbl_numbers) ;