函数中的NOT不适用于我的mysql版本

我有一个在mysql版本

5.5.44-0

上运行的语句，但是在mysql

4.0.24

有什么想法我可以改变，使它向后兼容

select distinct cust_id
from billing where billing.cust_id
not in (
select distinct billing_id from internet
);

这些是桌子

mysql> select * from billing;
+----+---------+-------+
| id | cust_id | cost  |
+----+---------+-------+
|  2 |      34 |   500 |
|  3 |      12 | 67700 |
|  4 |      99 |   100 |
|  5 |      99 |  1700 |
|  6 |    1450 |   800 |
|  7 |      88 |     0 |
|  8 |     222 |  5100 |
|  9 |     288 |  5100 |
| 10 |     329 |  5100 |
+----+---------+-------+


mysql> select * from internet;
+----+------------+------+
| id | billing_id | cost |
+----+------------+------+
|  1 |       1450 |  900 |
|  2 |         99 |  900 |
|  3 |        899 |  900 |
|  4 |        329 |  900 |
+----+------------+------+

在版本

5.5.44-0中

：

mysql> select distinct cust_id
    -> from billing where billing.cust_id
    -> not in (
    -> select distinct billing_id from internet
    -> );
+---------+
| cust_id |
+---------+
|      34 |
|      12 |
|      88 |
|     222 |
|     288 |
+---------+

在版本

4.0.24

中：

mysql> select distinct cust_id
    -> from billing where billing.cust_id
    -> not in (
    -> select distinct billing_id from internet
    -> );
ERROR 1064 (HY000): You have an error in your SQL syntax.  Check the manual that corresponds to your MySQL server version for the right syntax to use near 'select distinct billing_id from internet
)' at line 4

---

哇，不幸的是，您必须使用MySQL 4.0，它绝对是古老的，不支持大多数类型的子查询或子选择。您可以将查询重写为

左连接

，其中

WHERE

子句过滤

NULL

值，以指示与

notin（）等价的不匹配项

如果您能够在该服务器上获得更新的MySQL版本，则强烈建议您使用它。4.0版本线可以追溯到2002年，也就是MySQL生命周期的早期，它将缺少很多更重要的特性和安全改进

SELECT
  distinct cust_id
FROM
  billing
  -- Express the equivalence you matched with NOT IN() 
  -- as a left join ON condition
  LEFT JOIN internet ON billing.cust_id = internet.billing_id
WHERE
  -- A NULL value on the joined table indicates
  -- the relationship doesn't exist / there is no matching
  -- `billing_id` record in `internet` for the `cust_id`
  internet.billing_id IS NULL