如何选择在mysql中找到和未找到其输入数组的所有数据

这是我想要的桌子

选择在表中找到但未找到的数据，这两个数据都是我希望使用的联接或联合，我正在尝试使用此查询，但无法执行

    CREATE TABLE emp (
  empno decimal(4,0) NOT NULL,
  ename varchar(10) default NULL,
  job varchar(9) default NULL,
  mgr decimal(4,0) default NULL,
  hiredate date default NULL,
  sal decimal(7,2) default NULL,
  comm decimal(7,2) default NULL,
  deptno decimal(2,0) default NULL
);

INSERT INTO emp VALUES ('7369','SMITH','CLERK','7902','1980-12-17','800.00',NULL,'20');
INSERT INTO emp VALUES ('7499','ALLEN','SALESMAN','7698','1981-02-20','1600.00','300.00','30');
INSERT INTO emp VALUES ('7521','WARD','SALESMAN','7698','1981-02-22','1250.00','500.00','30');
INSERT INTO emp VALUES ('7566','JONES','MANAGER','7839','1981-04-02','2975.00',NULL,'20');
INSERT INTO emp VALUES ('7654','MARTIN','SALESMAN','7698','1981-09-28','1250.00','1400.00','30');
INSERT INTO emp VALUES ('7698','BLAKE','MANAGER','7839','1981-05-01','2850.00',NULL,'30');
INSERT INTO emp VALUES ('7782','CLARK','MANAGER','7839','1981-06-09','2450.00',NULL,'10');
INSERT INTO emp VALUES ('7788','SCOTT','ANALYST','7566','1982-12-09','3000.00',NULL,'20');
INSERT INTO emp VALUES ('7839','KING','PRESIDENT',NULL,'1981-11-17','5000.00',NULL,'10');






empno   ename    job       mgr         hiredate   sak        comm  depno   
'7369', 'SMITH', 'CLERK',   '7902', '1980-12-17', '800.00', NULL, '20'
'7499', 'ALLEN', 'SALESMAN', '7698', '1981-02-20', '1600.00', '300.00', '30'
'7521', 'WARD', 'SALESMAN', '7698', '1981-02-22', '1250.00', '500.00', '30'
'7566', 'JONES', 'MANAGER', '7839', '1981-04-02', '2975.00', NULL, '20'
'7654', 'MARTIN', 'SALESMAN', '7698', '1981-09-28', '1250.00', '1400.00', '30'
'7698', 'BLAKE', 'MANAGER', '7839', '1981-05-01', '2850.00', NULL, '30'
'7782', 'CLARK', 'MANAGER', '7839', '1981-06-09', '2450.00', NULL, '10'
'7788', 'SCOTT', 'ANALYST', '7566', '1982-12-09', '3000.00', NULL, '20'
'7839', 'KING', 'PRESIDENT', NULL, '1981-11-17', '5000.00', NULL, '10'

我想当我输入“史密斯，沃德，金，汤姆”

然后它应该像这样重新运行数据：

SELECT * FROM (emp)
WHERE  FIND_IN_SET(ename, 'SMITH,WARD,KING,TOM')

Union All
select  * from (emp)  where  !FIND_IN_SET(ename, 'SMITH,WARD,KING,TOM')

请告诉我怎么做香葱

我想以这种方式创建程序，以便通过“SMITH，ALLEN，TOM”

---

然后它应该以这种方式给出3行，如7369 | SMITH，7499 | ALLEN，null | TOM

一个helper表用于左连接/右连接概念，但它并没有那么简单

我在这里的回答（第三版）：

从修改后的答案

因此，上面是将csv映射到查询并从中生成表的一般形式

现在从上面创建一个派生表（

d

），通过

RIGHT JOIN

与op-code组合（该模式在op-code中显示）

结果:

select d.name as rtable_name,e.empno,e.ename,e.job,e.mgr,e.hiredate,e.sal,e.comm,e.deptno 
from emp e 
right join 
(   select SUBSTRING_INDEX(SUBSTRING_INDEX(@str, ',', 4k.id), ',', -1) name  
    from 4kTable 4k  
    cross join (select @str:='SMITH,WARD,KING,TOM') vars 
    on CHAR_LENGTH(@str) 
        -CHAR_LENGTH(REPLACE(@str, ',', ''))>=4k.id-1 
) d 
on d.name=e.ename; 

---

我不明白你的问题！“选择在表中找到的数据，但在两个数据中都找不到”-我不明白这是什么意思！您的示例结果只包含匹配的记录。看，假设我们的表id为1,2,3,4,5，在我的过程中，我发送了1,2,9,12，所以我想要4个结果，其中包含1，value1 | 2，value2 | 9，null | 12，null@shadow哦，好的，现在我得到了。您希望返回一个已填充间隙的列表。这个问题在这里已经被问过很多次了。是的，请建议我如何实现OK的这个可能的副本，等等，让我检查一下Thanx没有4kTable，我们无法实现这个问题？你可以使用fthiella通过他的联合策略显示的第二个块，但是因为我这里和那里有很多例程使用的帮助表（主要是关于

左连接的日期

）我想我会省去那个希望字符串包含100个项目的家伙。对于笨重且不可缩放的愚蠢的union STMT，我需要它，但我无法做到，因为我无法找到@Drew表中不存在的数据。请帮助我使用union

CREATE TABLE 4kTable
(   -- a helper table of about 4k consecutive ints
    id int auto_increment primary key,
    thing int null
)engine=MyISAM;

insert 4kTable (thing) values (null),(null),(null),(null),(null),(null),(null),(null),(null);
insert 4kTable (thing) select thing from 4kTable;
insert 4kTable (thing) select thing from 4kTable;
insert 4kTable (thing) select thing from 4kTable;
insert 4kTable (thing) select thing from 4kTable;
insert 4kTable (thing) select thing from 4kTable;
insert 4kTable (thing) select thing from 4kTable;
insert 4kTable (thing) select thing from 4kTable;
insert 4kTable (thing) select thing from 4kTable;
insert 4kTable (thing) select thing from 4kTable;
-- verify:
-- select min(id),max(id),count(*) from 4kTable;
-- 1 4608 4608

ALTER TABLE 4kTable ENGINE = InnoDB; -- *********** it is now InnoDB

select SUBSTRING_INDEX(SUBSTRING_INDEX(@str, ',', 4k.id), ',', -1) name 
from 
  4kTable 4k  
  cross join (select @str:='SMITH,WARD,KING,TOM') vars 
  on CHAR_LENGTH(@str) 
     -CHAR_LENGTH(REPLACE(@str, ',', ''))>=4k.id-1; 
+-------+
| name  |
+-------+
| SMITH |
| WARD  |
| KING  |
| TOM   |
+-------+

select d.name as rtable_name,e.empno,e.ename,e.job,e.mgr,e.hiredate,e.sal,e.comm,e.deptno 
from emp e 
right join 
(   select SUBSTRING_INDEX(SUBSTRING_INDEX(@str, ',', 4k.id), ',', -1) name  
    from 4kTable 4k  
    cross join (select @str:='SMITH,WARD,KING,TOM') vars 
    on CHAR_LENGTH(@str) 
        -CHAR_LENGTH(REPLACE(@str, ',', ''))>=4k.id-1 
) d 
on d.name=e.ename; 

+-------------+-------+-------+-----------+------+------------+---------+--------+--------+
| rtable_name | empno | ename | job       | mgr  | hiredate   | sal     | comm   | deptno |
+-------------+-------+-------+-----------+------+------------+---------+--------+--------+
| SMITH       |  7369 | SMITH | CLERK     | 7902 | 1980-12-17 |  800.00 |   NULL |     20 |
| WARD        |  7521 | WARD  | SALESMAN  | 7698 | 1981-02-22 | 1250.00 | 500.00 |     30 |
| KING        |  7839 | KING  | PRESIDENT | NULL | 1981-11-17 | 5000.00 |   NULL |     10 |
| TOM         |  NULL | NULL  | NULL      | NULL | NULL       |    NULL |   NULL |   NULL |
+-------------+-------+-------+-----------+------+------------+---------+--------+--------+