MySQL如何在一个集合中选择两个日志项之间的时间差?
我有一大组日志条目需要对其进行分析。我要做的是为每组日志选择开始和完成条目之间的时间差。我该怎么做呢MySQL如何在一个集合中选择两个日志项之间的时间差?,mysql,data-analysis,Mysql,Data Analysis,我有一大组日志条目需要对其进行分析。我要做的是为每组日志选择开始和完成条目之间的时间差。我该怎么做呢 Sample Log Set: ExecuteTime, Entry, TrackKey 7.2408730984, Start update, 487996b0608b0006bfbe5501217c76bde879b728 9.9038851261, Complete update, 487996b0608b0006bfbe5501217c76bde879b728 未经测试: SELEC
Sample Log Set:
ExecuteTime, Entry, TrackKey
7.2408730984, Start update, 487996b0608b0006bfbe5501217c76bde879b728
9.9038851261, Complete update, 487996b0608b0006bfbe5501217c76bde879b728
未经测试:
SELECT * FROM Table AS t1 LEFT JOIN (SELECT MIN(Sample) AS Min, MAX(Sample) AS Max FROM Table) AS t2 ON t1.TrackKey = t2.TrackKey
更新:
SELECT
(t3.End - t2.Start) AS Total
FROM Table AS t1
LEFT JOIN
(
SELECT
Sample AS Start
FROM
Table
WHERE
Entry = "Start update"
) AS t2 ON t1.TrackKey = t2.TrackKey
LEFT JOIN
(
SELECT
Sample AS End
FROM
Table
WHERE
Entry = "Complete update"
) AS t3 ON t1.TrackKey = t3.TrackKey
我假设开始时间是最小的,结束时间是最大的。如果不是这样,这个查询将是错误的
select TrackKey, (MAX(ExecuteTime) - MIN(ExecuteTime)) as time_difference
FROM table
WHERE Entry IN('Start update', 'Complete update')
GROUP BY TrackKey