Mysql 如何删除表1中不存在的行

嘿，伙计们，需要你们的帮助，我很累，现在我累了，找不到出路

我有两个表&我确实想删除那些表2中没有外来id的行，下面我已经按结构提到了

表1

     Column A(Foreign)     Column B  

     record A              Some thing
     record B              Some thing
     record c              Some thing

表2

     Column A(Foreign)     Column B  

     record A              Some thing
     record B              Some thing

现在实际上我想删除表2中没有的记录C。有什么办法吗

顺便说一下，糟糕的表名和列名

此处演示-

此功能：

DELETE VM.* FROM `Table1` AS VM
LEFT JOIN `Table2` AS VL
ON VL.`Column A(Foreign)` = VM.`Column A(Foreign)d`
WHERE VL.`Column A(Foreign)` IS NULL

试试这个，工作

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请尽你最大的努力，即使它没有产生正确的结果。至少我们会知道什么是不需要解释的。你确定你得到了OP想要的结果吗？@PM77-1谢谢你指出。现在请检查我已经更正了代码。

DELETE VM.* FROM `Table1` AS VM
LEFT JOIN `Table2` AS VL
ON VL.`Column A(Foreign)` = VM.`Column A(Foreign)d`
WHERE VL.`Column A(Foreign)` IS NULL

create table t1 (
  a varchar(16),
  b varchar(16)
);

create table t2 (
  a varchar(16),
  b varchar(16)
);

insert into t1 values
('record A', 'Some thing'),
('record B', 'Some thing'),
('record c', 'Some thing');

insert into t2 values
('record A', 'Some thing'),
('record B', 'Some thing');

delete t1
FROM  t1 left outer join t2 
ON t1.a = t2.a
where t2.a is null