Mysql 如何在单个查询中获得不同列中的奇偶ID？

例如，我有一张如下所示的表格。。我希望在偶数/奇数ID的基础上有单独的列

-----------------------------------------------------
| ID  |  Names
-----------------------------------------------------
| 1   |  Name1
-----------------------------------------------------
| 2   |  Name2
-----------------------------------------------------
| 3   |  Name3
-----------------------------------------------------
| 4   |  Name4
-----------------------------------------------------

我想设计一个查询，可以给我

-------------------
| Even  |  Odd    |
-------------------
| Name2 |  Name1  |
-------------------
| Name4 |  Name3  |
-------------------

---

如果要获得奇数或偶数，请使用下一个查询： 选择奇数记录：

SELECT * FROM table WHERE ID % 2 = 1

选择偶数

SELECT * FROM table WHERE ID % 2 = 0

如果要装饰为两列，请尝试下一种解决方案：

SELECT
    odd.name as Odd,
    (SELECT name FROM table WHERE ID = odd.ID + 1 ) as Even
FROM
    table as odd
WHERE
    odd.ID % 2 = 1

使用模运算符%查找奇偶性（偶数或奇数性质）

…其中id%2等于0

这将在结果中为您提供均匀的id

---

不等于0的是奇数id。

如果您的id列包含序号，且序号之间没有任何间隙，则：

SELECT t1.name as ODD,
       t2.name as EVEN
FROM   YourTable t1
       left outer JOIN YourTable t2
         ON t1.Id + 1 = t2.Id
where t1.Id%2 = 0

注意：如果数字之间存在间隙，则一些

奇数

将显示为

空

，或者如果间隙大于3，则可能跳过该

名称

select 
  max(case id%2 when 1 then name end) as odd,
  max(case id%2 when 0 then name end) as even
from your_table
group by floor((id+1)/2)

---

上述结果集可通过以下代码实现-

SELECT Even, Odd   
FROM (SELECT *, ROW_NUMBER()OVER(ORDER BY Even) AS ROW   
    FROM (SELECT CASE WHEN ID % 2 = 0 THEN Names ELSE NULL END AS 'Even'  
    FROM TableName)TAB1  
    WHERE Even IS NOT NULL)T1  
FULL OUTER JOIN   
(SELECT *, ROW_NUMBER()OVER(ORDER BY Odd) AS ROW  FROM  
    (SELECT CASE WHEN ID % 2 = 1 THEN Names ELSE NULL END AS 'Odd'  
    FROM TableName) TAB2  
    WHERE Odd IS NOT NULL) T2  
ON T1.ROW=T2.ROW  

---

如果您的ID是连续的，那么

SELECT tb1.ODD, tb2.EVEN
FROM
(
    SELECT Id, name ODD
    FROM YourTable
    where (`Id` % 2) = 1
 ) AS tb1 

 JOIN 

 (SELECT Id, name EVEN
  FROM  YourTable
  WHERE (`Id` % 2) = 0
 ) AS tb2 

ON (tb1.Id + 1 = tb2.Id)

WHERE tb1.ODD IS NOT NULL
ORDER BY tb1.Id

---

这是两个不同的问题。。我想设计一个可以在同一个查询的不同列中为我提供一个关于使用PIVOT的SQL SERVER的很好的答案，然后看到这是mySQL。。。无论如何，如果你想看的话，SQLFIDLE是一个很好的解决方案。您使用按楼层分组（（id+1）/2）而不是按单元分组（（id）/2）的任何原因？