Mysql SQL计数两列并进行减法运算

晚安。我遇到了这个问题，我尝试了子查询和案例，但没有成功

当玩家在我的游戏中杀死某人时，会向数据库中添加一条新记录，该记录包含杀手的ID和被杀玩家的ID，因此一段时间后，表将如下所示：

killer_id  |  death_id
100        |  200        -> (Player 100 Killed player 200)
100        |  200
100        |  200
200        |  100
300        |  100
300        |  200

我试图得到每个玩家的分数，基于他们的杀戮减去他们的死亡，因此基于上述数据：

Rank:
Pos 1. player 300 / 2 Points  (2 Kills - 0 deaths)
Pos 2. player 100 / 1 Point   (3 Kills - 2 deaths)
Pos 3. player 200 / -3 Points (1 Kills - 4 deaths)

我想在一个SQL查询上执行此操作，但我被卡住了。。。任何提示都将不胜感激。

您可以使用union all和aggregation：

select player_id, sum(cnt) score
from (
    select killer_id player_id, 1 cnt from mytable
    union all select death_id, -1 from mytable
) t
group by player_id
order by score desc

select player_id, sum(points)
from ((select killer_id as player_id, 1 as points
       from t
      ) union all
      (select death_id, -1 as points
       from t
      ) 
     ) kd
group by player_id
order by sum(points) desc;

如果您还需要玩家排名，可以使用窗口函数，这需要MySQL 8.0：

select rank() over(order by sum(cnt) desc) pos, player_id, sum(cnt) score
from (
    select killer_id player_id, 1 cnt from mytable
    union all select death_id, -1 from mytable
) t
group by player_id
order by score desc

您可以使用union all和聚合：

select player_id, sum(cnt) score
from (
    select killer_id player_id, 1 cnt from mytable
    union all select death_id, -1 from mytable
) t
group by player_id
order by score desc

select player_id, sum(points)
from ((select killer_id as player_id, 1 as points
       from t
      ) union all
      (select death_id, -1 as points
       from t
      ) 
     ) kd
group by player_id
order by sum(points) desc;

如果您还需要玩家排名，可以使用窗口函数，这需要MySQL 8.0：

select rank() over(order by sum(cnt) desc) pos, player_id, sum(cnt) score
from (
    select killer_id player_id, 1 cnt from mytable
    union all select death_id, -1 from mytable
) t
group by player_id
order by score desc

您可以使用“全部联合”和“聚合”：

select player_id, sum(cnt) score
from (
    select killer_id player_id, 1 cnt from mytable
    union all select death_id, -1 from mytable
) t
group by player_id
order by score desc

select player_id, sum(points)
from ((select killer_id as player_id, 1 as points
       from t
      ) union all
      (select death_id, -1 as points
       from t
      ) 
     ) kd
group by player_id
order by sum(points) desc;

您可以使用“全部联合”和“聚合”：

select player_id, sum(cnt) score
from (
    select killer_id player_id, 1 cnt from mytable
    union all select death_id, -1 from mytable
) t
group by player_id
order by score desc

select player_id, sum(points)
from ((select killer_id as player_id, 1 as points
       from t
      ) union all
      (select death_id, -1 as points
       from t
      ) 
     ) kd
group by player_id
order by sum(points) desc;

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谢谢，我不是sql方面的专家，所以这对我帮助很大。谢谢，我不是sql方面的专家，所以这对我帮助很大。