Neo4j 如何在cypher中按两个条件查找节点列表？

我有3种节点：标记、城市和地点

我想写一个包含两个列表的查询

 [tag1,tag2,....]

及

我想找到一个位于这些城市之一的地方列表，并将它们从标签尽可能多的城市排序到标签较少的城市

 MATCH (spot:Spot)-[:located_at]->(city:City ) 
 where city.id IN ["22","23"]
 with spot as sp,city as cy
 MATCH (sp:Spot)-[rels:tagged_by]->(tag:Tag)
 where tag.id IN ["16", "10151", "21"]
 with sp as fsp, tag
 RETURN fsp, tag,    count(distinct fsp.id) AS cnt
 order by cnt desc

我尝试了该查询，但不知何故无法列出节点及其标记

请帮忙！

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提前谢谢

尝试子查询方法：

选择城市->查找点->查找该点的标记

MATCH (city:City)
OPTIONAL MATCH (spot:Spot)-[:located_at]->(city) 
OPTIONAL MATCH (spot)-[rels:tagged_by]->(tag:Tag)
where city.id IN ["22","23"]
where tag.id IN ["16", "10151", "21"]
RETURN spot, tag, count(distinct fsp.id) AS cnt
order by cnt desc

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我将如何处理这个问题是个问题

MATCH (spot:Spot)-[:located_at]->(city:City)
RETURN city,spot,size(spot-[:tagged_by]->()) as tags order by tags desc

所以现在你得到了所有标记最多的点。显然，您可以根据需要添加过滤器

MATCH (spot:Spot)-[:located_at]->(city:City) where city.name = "London"
RETURN city,spot,size(spot-[:tagged_by]->())  as tags order by tags desc

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我是这样做的。我的错误是不知道如何计算关系，也不知道如何正确使用聚合

 match (city:City)<-[]-(spot:Spot) 
 where city.id in ["22","23"] 
 match (spot)-[rel]->(tag:Tag) 
 where tag.id in ["16", "10151", "21"] 
 return spot, count(rel) as rel_count 
 order by rel_count desc limit 100

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这是我想要的

这里有一个有用的链接，用于在neo4j@TomažBratanič中进行jaccard索引。我很难让带有标记的节点在这些城市中，并且它们的所有标记都在这些给定标记内。似乎我上面的代码是错误的：

 match (city:City)<-[]-(spot:Spot) 
 where city.id in ["22","23"] 
 match (spot)-[rel]->(tag:Tag) 
 where tag.id in ["16", "10151", "21"] 
 return spot, count(rel) as rel_count 
 order by rel_count desc limit 100