Notepad++ 使用记事本+；基于单行文本提取特定的文本行+；

我在一个巨大的文本文件中有下面几行，我想提取前面的行和其他行。如果集合不包含行D，则应忽略集合

LineA
LineB 
LineC

Line1
Line2 
Line3
LineD

Linex
LineY 
LineZ

Line4
Line5 
Line6
LineD

输出应该是

Line1
Line2 
Line3
LineD

Line4
Line5 
Line6
LineD

• Ctrl+H
• 查找内容：

  （？：\A |\R\R）（？：（？！LineD）[\s\s]）*？（？=\R\R |\z）

• 替换为：

  留空

• 检查匹配案例
• 检查环绕
• 检查正则表达式
• 取消选中

  。匹配换行符

• 全部替换

说明：

(?:\A|\R\R)     # non capture group, beginning of file OR 2 linebreaks
(?:             # non capture group
  (?!LineD)     # negative lookahead, make sure sure we haven't "LineD"
  [\s\S]        # any character, including linebreak
)*?             # end group, may appear 0 or more times, not greedy
(?=\R\R|\z)     # positive lookahead, make sure we have a double linebreak OR end of file after.

屏幕截图（之前）：

(?:\A|\R\R)     # non capture group, beginning of file OR 2 linebreaks
(?:             # non capture group
  (?!LineD)     # negative lookahead, make sure sure we haven't "LineD"
  [\s\S]        # any character, including linebreak
)*?             # end group, may appear 0 or more times, not greedy
(?=\R\R|\z)     # positive lookahead, make sure we have a double linebreak OR end of file after.

屏幕截图（之后）：

(?:\A|\R\R)     # non capture group, beginning of file OR 2 linebreaks
(?:             # non capture group
  (?!LineD)     # negative lookahead, make sure sure we haven't "LineD"
  [\s\S]        # any character, including linebreak
)*?             # end group, may appear 0 or more times, not greedy
(?=\R\R|\z)     # positive lookahead, make sure we have a double linebreak OR end of file after.

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请格式化您的问题，并向我们显示实际文本，而不是上面显示的文本。这听起来像是正则表达式的工作。