Objective c 如何创建一个NSDictionary，其中NSArray of NString代表key，bunch of int代表value？

问题是：

NSArray * alphabets = [NSArray arrayWithObjects:@"a",@"b",@"c",@"d",@"e",@"f",@"g",@"h",@"i",@"j",@"k",@"l",@"m",@"n",@"o",@"p",@"q",@"r",@"s",@"t",@"u",@"v",@"w",@"x",@"y",@"z",nil];
NSDictionary * alphaToNum = [NSDictionary dictionaryWithObject:alphabets forKey:1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26];
//I know above line meant to not work I just brought it here as an example

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如何创建如上所述的有效字典？

您只能将对象用作

NSDictionary

中的键或值，因此必须使用

NSNumber

作为整数键的包装器

NSMutableDictionary *alphaToNum = [NSMutableDictionary dictionary];
NSArray *alphabet = [NSArray arrayWithObjects:@"a",@"b",@"c",@"d",@"e",@"f",@"g",@"h",@"i",@"j",@"k",@"l",@"m",@"n",@"o",@"p",@"q",@"r",@"s",@"t",@"u",@"v",@"w",@"x",@"y",@"z",nil];
NSInteger index = 0;

for(NSString *character in alphabet)
{
    index ++;
    [alphaToNum setObject:character forKey:[NSNumber numberWithInteger:index]];
}

哦，你是第一个删除了我的答案