Objective c 如何根据以前的操作进行不同的操作'；objC中的发件人是谁？

假设我有两个按钮“switch”和“close”，它们都连接到popUpAreYouSureView，点击该按钮时会取消隐藏名为areYouSureView的视图。“确定吗？”视图有两个按钮：“是”和“否”，分别连接到pressdYes和pressedNo

当我按下“是”或“否”时，我将检查“开关”或“关闭”按钮是否取消隐藏我的视图。根据取消隐藏视图的按钮，我希望执行不同的逻辑。我遇到的问题是，如何知道“开关”或“关闭”按钮是否在不存储该信息的情况下取消隐藏我的视图

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什么是干净的方法？我查看了代理，但这似乎不起作用，因为我在切换和关闭案例中都传递了相同的代理。选择器也有同样的问题。我是否必须存储（id）发送器，该发送器告诉我上一个动作是否来自开关或关闭按钮，以便连接到“是”或“否”按钮的动作可以查找它并找出要执行的逻辑？

您需要跟踪导致该动作的原因，这是无法避免的。因此，请充分利用

sender

参数

- (IBAction)popUpAreYouSureView:(id)sender {
    self.areYouSureView.hidden = NO;
}

- (IBAction)pressedYes {
    // if sender from popUpAreYouSureView was switch, do something

    // else if sender from popUpAreYouSureView was close, do something else
} 

- (IBAction)pressedNo {
    // if sender from popUpAreYouSureView was switch, do something

    // else if sender from popUpAreYouSureView was close, do something else
} 

一个快速（但不是很漂亮）的解决方案是使用areYouSureView视图的“tag”属性。 给每个按钮一个不同的标签（例如，1表示关闭，2表示开关），然后您可以执行以下操作：

__weak UIButton* m_buttonSelected;

- (IBAction)popUpAreYouSureView:(id)sender {
    self.areYouSureView.hidden = NO;
    m_buttonSelected = (UIButton*)sender;
}

- (IBAction)pressedYes {
    // if sender from popUpAreYouSureView was switch, do something
    if ([m_buttonSelected isEqual:self.switchButton]) {
        ...
    }
    // else if sender from popUpAreYouSureView was close, do something else
    else if ([m_buttonSelected isEqual:self.closeButton]) {
        ...
    }

    m_buttonSelected = nil;
} 

- (IBAction)pressedNo {
    // if sender from popUpAreYouSureView was switch, do something
    if ([m_buttonSelected isEqual:self.switchButton]) {
        ...
    }
    // else if sender from popUpAreYouSureView was close, do something else
    else if ([m_buttonSelected isEqual:self.closeButton]) {
        ...
    }

    m_buttonSelected = nil;
} 

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您可以尝试在

popUpAreYouSureView

中重新定义按钮操作：

- (IBAction)popUpAreYouSureView:(id)sender {
    self.areYouSureView.hidden = NO;
    self.areYouSureView.tag = ((UIView*)sender).tag; 
}

- (IBAction)pressedYes {
    if (self.areYouSureView.tag == 1)
        NSLog(@"Button 1");
    else
        NSLog(@"Button 2");
} 

- (IBAction)pressedNo {
    if (self.areYouSureView.tag == 1)
        NSLog(@"Button 1");
    else
        NSLog(@"Button 2");
} 

- (IBAction)popUpAreYouSureView:(id)sender {

  if ([sender...]) {
    [self.yesButton addTarget:self action:@selector(...) forControlEvents:...];
    [self.yesButton addTarget:self action:@selector(...) forControlEvents:...];
  } else {
    [self.yesButton addTarget:self action:@selector(...) forControlEvents:...];
    [self.yesButton addTarget:self action:@selector(...) forControlEvents:...];
  }
}

一个稍微好一点的解决方案是在

按Yes

和

按No

实现中使用委托，注意在

popUpAreYouSureView

中设置委托：

- (IBAction)popUpAreYouSureView:(id)sender {
    self.areYouSureView.hidden = NO;
    self.areYouSureView.tag = ((UIView*)sender).tag; 
}

- (IBAction)pressedYes {
    if (self.areYouSureView.tag == 1)
        NSLog(@"Button 1");
    else
        NSLog(@"Button 2");
} 

- (IBAction)pressedNo {
    if (self.areYouSureView.tag == 1)
        NSLog(@"Button 1");
    else
        NSLog(@"Button 2");
} 

- (IBAction)popUpAreYouSureView:(id)sender {

  if ([sender...]) {
    [self.yesButton addTarget:self action:@selector(...) forControlEvents:...];
    [self.yesButton addTarget:self action:@selector(...) forControlEvents:...];
  } else {
    [self.yesButton addTarget:self action:@selector(...) forControlEvents:...];
    [self.yesButton addTarget:self action:@selector(...) forControlEvents:...];
  }
}

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这两种方法都应该有效。

什么类型是

self。你确定要查看
？