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Objective c 块目标c内的访问属性_Objective C_Properties_Block - Fatal编程技术网

Objective c 块目标c内的访问属性

Objective c 块目标c内的访问属性,objective-c,properties,block,Objective C,Properties,Block,我无法访问此块中的任何属性。就像我在.h文件中创建了UIImage属性,但我无法在该结果块中访问该属性。下一个解决方案是,您可以从整个控制器创建块属性,如下所示: - (IBAction)saveBtn:(id)sender { UIImage* imageToSave = [self imageByCombiningImage:self.backgroundImage.image withImage:self.tempImage.image]; ALAssetsLibrary

我无法访问此块中的任何属性。就像我在.h文件中创建了UIImage属性,但我无法在该结果块中访问该属性。

下一个解决方案是,您可以从整个控制器创建块属性,如下所示:

- (IBAction)saveBtn:(id)sender {
    UIImage* imageToSave = [self imageByCombiningImage:self.backgroundImage.image withImage:self.tempImage.image];
    ALAssetsLibrary *library = [[ALAssetsLibrary alloc] init];
    // Request to save the image to camera roll

    [library writeImageToSavedPhotosAlbum:[imageToSave CGImage] orientation:(ALAssetOrientation)[imageToSave imageOrientation] completionBlock:^(NSURL *assetURL, NSError *error){
        if (error) {
            NSLog(@"error");
        } else {
            CGFloat compression = 0.0;         
            NSData *imageData = UIImageJPEGRepresentation(imageToSave, compression);
            UIImage *compressedImage = [[UIImage alloc]initWithData:imageData];
            NSMutableString *imageName = [[NSMutableString alloc] initWithCapacity:0];

            CFUUIDRef theUUID = CFUUIDCreate(kCFAllocatorDefault);
            if (theUUID) {
                [imageName appendString:CFBridgingRelease(CFUUIDCreateString(kCFAllocatorDefault, theUUID))];
                CFRelease(theUUID);
            }
            [imageName appendString:@".png"];

            NSLog(@"Image name: %@", imageName);

            //Image Data to web service
            [self uploadImage:UIImageJPEGRepresentation(compressedImage, 1.0) filename:imageName];

            _savedImageURL = assetURL;
            [library assetForURL:_savedImageURL
                     resultBlock:resultblock
                    failureBlock:failureblock];
    }];
}

ALAssetsLibraryAssetForURLResultBlock resultblock = ^(ALAsset *myasset)
{
    ALAssetRepresentation *rep = [myasset defaultRepresentation];
    CGImageRef iref = [rep fullResolutionImage];
    if (iref) {
        UIImage *largeimage = [UIImage imageWithCGImage:iref];
        //image Property needs to be access here
    }
};
在块内部,您可以使用此属性访问:

__block MyViewController *blocksafeSelf = self;
或调用方法:

blocksafeSelf.myProperty;

如果您发布的代码确实是您正在使用的代码,那么它将定义一个引用块的变量。但是该变量不是类的一部分,因此不能引用任何实例变量

相反,该变量位于“C顶层”,不在任何类中。您可能希望将其转换为实例变量,例如:

dispatch_async(dispatch_get_main_queue(), ^
      [blocksafeSelf processNewMessage:text]  
});

您也可以使用属性来代替。

需要更多信息。这个区块是在哪里定义的?你有什么错误?您的注释提示您试图访问实例变量(可能由属性生成),这才是您真正想要的。请编辑您的问题并提供更多代码和详细信息。请勿在评论中发布代码,谢谢。您在哪里分配块?您发布的代码无效。请修复它。您如何知道无法访问该街区中的某个属性?我们希望您清理代码,请格式化,并查看结果。您的意思是“无法访问”读取或写入,还是两者兼而有之?
\u block
仅用于变量将被分配到的情况<代码>self未分配到此处的任何位置。但您也未在此处使用
self
或任何实例变量。如果您这样做了,它将创建一个保留循环。@newacct:您知道在块之前创建对
self
的弱引用并在块内部使其变强以打破保留循环的诀窍吗?
@interface MyClass : SomeSuperClass
{
    // Define an instance variable.
    ALAssetsLibraryAssetForURLResultBlock resultblock;
}
@end

@implementation MyClass

- (void)someMethod
{
    // Initialize the variable in `init`, `viewDidLoad` or whichever
    // method suits you.
    resultblock = ^(ALAsset *myasset)
    {
        ALAssetRepresentation *rep = [myasset defaultRepresentation];
        CGImageRef iref = [rep fullResolutionImage];
        if (iref) {
            UIImage *largeimage = [UIImage imageWithCGImage:iref];
           //image Property needs to be access here
        }
   };
}

@end