Objective c 如何将枚举作为参数传递给Objective中的函数

头文件如下所示：

enum RatingsEnum
{
    userRating,
    criticRating,
};

@interface SFMovie : NSObject

- (NSNumber *)getRating:(NSDictionary *)movieDic :(enum RatingsEnum) rating;

@end

如何使用此方法获取评级？我不知道如何通过枚举。我的电话号码：

- (void) testGetCriticRatingMethod{

    NSMutableDictionary *ratingDictionary = [[NSMutableDictionary alloc]init];
    [ratingDictionary setObject:@"Certified Fresh" forKey:@"critics_rating"];
    [ratingDictionary setObject:@"70" forKey:@"critics_score"];
    [ratingDictionary setObject:@"Certified Fresh" forKey:@"audience_rating"];
    [ratingDictionary setObject:@"87" forKey:@"audience_score"];
    SFMovie *movie = [[SFMovie alloc]init];
    enum RatingsEnum ratings;
    NSInteger userRating = [movie getRating:ratingDictionary rating:userRating];
}

这将产生以下警告： “SFMovie”没有可见的@interface声明选择器“getRating:rating:”

---

有人能给我介绍一个好的枚举教程吗？谢谢大家。

这与

枚举或参数类型无关。你的语法完全错误。声明的方法的名称是
getRating:：
。正确的呼叫看起来像

[movie getRating:ratingDictionary :userRating];

将标签添加到第二个参数

- (NSNumber *)getRating:(NSDictionary *)movieDic ofType:(enum RatingsEnum)rating;

改变

 enum RatingsEnum ratings;
 NSInteger userRating = [movie getRating:ratingDictionary rating:userRating];

到

改变

 enum RatingsEnum ratings;
 NSInteger userRating = [movie getRating:ratingDictionary rating:userRating];

到

知道了。谢谢你，乔希。这真的与枚举无关。这只是一般的命名方法。是的，谢谢。在这里提问之前，我没有花足够的时间进行调试：（.在将问题放到stackoverflow上之后，我看到了错误：(
 enum RatingsEnum ratings;
 NSInteger userRating = [movie getRating:ratingDictionary rating:userRating];

 enum RatingsEnum ratings = userRating;
 NSNumber *ratingFromUser = [movie getRatingWithDictionary:ratingDictionary ratingEnum:ratings];