Objective c NSMutableArray覆盖最后一个对象

我在循环外初始化了nsmutablearray和nsmutable dictinay，而不是将最后一个对象覆盖到所有数组

NSMutableDictionary *dictNew=[[NSMutableDictionary alloc]init];
NSMutableArray *newArr =[[NSMutableArray alloc]init];
//dictNew=[[NSMutableDictionary alloc]init];

for (int i=0; i<[[[contactsData valueForKey:@"firstName"] objectAtIndex:0] count]; i++)
{
    [dictNew setObject:[[[contactsData valueForKey:@"firstName"]objectAtIndex:0]objectAtIndex:i] forKey:@"firstName"]:
    [dictNew setObject:[[[contactsData valueForKey:@"lastName"]objectAtIndex:0]objectAtIndex:i] forKey:@"lastName"];
    [dictNew setObject:[[[contactsData valueForKey:@"phones"]objectAtIndex:0]objectAtIndex:i] forKey:@"phones"];
    NSLog(@"%@",dictNew);
    [newArr addObject:dictNew];
    NSLog(@"newarr %@",newArr);
}

NSMutableDictionary*dictNew=[[NSMutableDictionary alloc]init]；
NSMutableArray*newArr=[[NSMutableArray alloc]init]；
//dictNew=[[NSMutableDictionary alloc]init]；
对于（int i=0；i你不能像那样重复使用
dictNew
。你每次迭代都需要一个新的实例。当你拥有它时，你会一次又一次地将同一个字典添加到数组中

试试这个：

NSMutableArray *newArr = [[NSMutableArray alloc]init];
for (int i = 0; i < [[[contactsData valueForKey:@"firstName"] objectAtIndex:0] count]; i++) {
    NSMutableDictionary *dictNew=[[NSMutableDictionary alloc]init];
    [dictNew setObject:[[[contactsData valueForKey:@"firstName"]objectAtIndex:0]objectAtIndex:i] forKey:@"firstName"]:
    [dictNew setObject:[[[contactsData valueForKey:@"lastName"]objectAtIndex:0]objectAtIndex:i] forKey:@"lastName"];
    [dictNew setObject:[[[contactsData valueForKey:@"phones"]objectAtIndex:0]objectAtIndex:i] forKey:@"phones"];
    NSLog(@"%@",dictNew);
    [newArr addObject:dictNew];
    NSLog(@"newarr %@",newArr);
}

NSMutableArray*newArr=[[NSMutableArray alloc]init]；
对于（int i=0；i<[[contactsdatavalueforkey:@“firstName”]objectAtIndex:0]计数]；i++）{
NSMutableDictionary*dictNew=[[NSMutableDictionary alloc]init]；
[dictNew setObject:[[contactsData valueForKey:@“firstName”]objectAtIndex:0]objectAtIndex:i]forKey:@“firstName”]：
[dictNew setObject:[[contactsData valueForKey:@“lastName”]objectAtIndex:0]objectAtIndex:i]forKey:@“lastName”]；
[dictNew setObject:[[contactsData valueForKey:@“电话”]objectAtIndex:0]objectAtIndex:i]forKey:@“电话”]；
NSLog（@“%@”，新的）；
[newArr addObject:dictNew]；
NSLog（@“newarr%@”，newarr）；
}

我还建议进行一些小的改进和清理：

NSMutableArray *newArr = [[NSMutableArray alloc] init];
NSArray *firstNames = [[contactsData valueForKey:@"firstName"] objectAtIndex:0];
for (NSInteger i = 0; i < firstNames.count; i++) {
    NSMutableDictionary *dictNew = [[NSMutableDictionary alloc] init];
    dictNew[@"firstName"] = firstNames[i];
    dictNew[@"lastName"] = [[[contactsData valueForKey:@"lastName"] objectAtIndex:0] objectAtIndex:i];
    dictNew[@"phones"] = [[[contactsData valueForKey:@"phones"] objectAtIndex:0] objectAtIndex:i];
    NSLog(@"dictNew = %@", dictNew);
    [newArr addObject:dictNew];
}
NSLog(@"newArr = %@", newArr);

NSMutableArray*newArr=[[NSMutableArray alloc]init]；
NSArray*firstNames=[[contactsData valueForKey:@“firstName”]对象索引：0]；
对于（NSInteger i=0；i
请发布
NSLog（）
的输出，并美化代码（缩进）。此外，如果将对内部数组的引用指定给引用变量，代码的可读性会更好。