Opencv 什么'；不失真点有什么问题吗 float k[]={1531.49,01267.78,01521.439952.078,0,0,1}； 浮点数d[]={-0.27149,0.15384,0.0046，-0.0026}； CvMat camera1=CvMat（3，3，CV_32FC2，k）； CvMat distCoeffs1=CvMat（1,4，CV_32FC2，d）； 常量int npoints=4；//指定的点数 //点初始化。 //在本例中，只有2个PONT，在实际代码中，它们是从文件中读取的。 浮点输入_点[npoints][4]={{0,0}，{25601920}；//其余的将设置为0 CvMat*src=cvCreateMat（1，npoints，CV_32FC2）； CvMat*dst=cvCreateMat（1，npoints，CV_32FC2）； //填充src矩阵 float*src_ptr=（float*）src->data.ptr； 对于（int-pi=0；pi

我希望使用CVUnsortPoints函数。并使用示例代码进行测试。当我使用VS2012运行时，它不起作用。它说“src.size与dst.size不匹配”。因为我是OpenCV的新手。有人能帮我吗？ 非常感谢。

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vs2012

的运行结果再次，<强> > <强>使用OpenCV的C++ API，而不是被禁止的C 1：

        float  k[]={1531.49,0,1267.78,0,1521.439,952.078,0,0,1};
    float  d[]={-0.27149,0.15384,0.0046,-0.0026};

    CvMat camera1=cvMat( 3, 3, CV_32FC2, k );
    CvMat distCoeffs1=cvMat(1,4,CV_32FC2,d);
    const int npoints = 4; // number of point specified 

// Points initialization. 
// Only 2 ponts in this example, in real code they are read from file.

float input_points[npoints][4] = {{0,0}, {2560, 1920}}; // the rest will be set to 0

CvMat * src = cvCreateMat(1, npoints, CV_32FC2);
CvMat * dst = cvCreateMat(1, npoints, CV_32FC2);

// fill src matrix
float * src_ptr = (float*)src->data.ptr;
for (int pi = 0; pi < npoints; ++pi) {
    for (int ci = 0; ci < 2; ++ci) {
        *(src_ptr + pi * 2 + ci) = input_points[pi][ci];
    }
}

cvUndistortPoints(src, dst, &camera1, &distCoeffs1);

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请避免使用opencv遗留的c-api。哦，很抱歉没有注意到这一点。我认为dst变量应该有四个元素。正如您所看到的，结果可能是错误的。您能帮助我吗？

Mat_<float> cam(3,3); cam << 1531.49,0,1267.78,0,1521.439,952.078,0,0,1;
Mat_<float> dist(1,5); dist <<-0.27149,0.15384,0.0046,-0.0026;

const int npoints = 4; // number of point specified 

// Points initialization. 
// Only 2 ponts in this example, in real code they are read from file.
Mat_<Point2f> points(1,npoints);
points(0) = Point2f(0,0);
points(1) = Point2f(2560, 1920);

Mat dst; // leave empty, opencv will fill it.
undistortPoints(points, dst, cam, dist);

cerr << dst;

[-0.90952414, -0.69702172, 0.92829341, 0.69035494, -0.90952414, -0.69702172, -0.90952414, -0.69702172]