Oracle 从当前行到最后一行的计数
我需要以下面的方式提取数据Oracle 从当前行到最后一行的计数,oracle,Oracle,我需要以下面的方式提取数据 progress_CMC_status progress_cmc_status_numbers cmc_status_numbers Mature Draft 2 5 Review 0 3 Final Draft
progress_CMC_status progress_cmc_status_numbers cmc_status_numbers
Mature Draft 2 5
Review 0 3
Final Draft 0 3
Final Comment 0 3
Final Document 2 3
Archived Document 1 1
progress_CMC_status progress_cmc_status_numbers cmc_status_numbers
Mature Draft 2 5
Review 0 0
Final Draft 0 0
Final Comment 0 0
Final Document 2 3
Archived Document 1 1
WITH sta AS
(SELECT 'Mature' "status1"
FROM DUAL
UNION
SELECT 'Review'
FROM DUAL
UNION
SELECT 'Final Draft'
FROM DUAL
UNION
SELECT 'Final Comment'
FROM DUAL
UNION
SELECT 'Final Document'
FROM DUAL
UNION
SELECT 'Archived'
FROM DUAL)
SELECT DECODE ("stat",
'Mature', 'Mature Draft',
'Review', 'Review',
'Final Draft', 'Final Draft',
'Final Comment', 'Final Comment',
'Final Document', 'Final Document',
'Archived', 'Archived Document'
) AS "progress_CMC_status",
NVL
(TO_CHAR ("progress_cmc_status_numbers"),
0
) AS "progress_cmc_status_numbers",
NVL (TO_CHAR ("cmc_status_numbers"), 0) AS "cmc_status_numbers"
FROM (SELECT "status1" AS "stat",
NVL
(TO_CHAR (NULL),
"progress_cmc_status_numbers"
) AS "progress_cmc_status_numbers",
NVL (TO_CHAR (NULL),
"cmc_status_numbers"
) AS "cmc_status_numbers"
FROM sta
LEFT JOIN
(SELECT VALUE AS "progress_CMC_status",
COUNT (*) AS "progress_cmc_status_numbers",
SUM (COUNT (*)) OVER (ORDER BY DECODE
(VALUE,
'Mature', 0,
'Review', 1,
'Final Draft', 2,
'Final Comment', 3,
'Final Document', 4,
'Archived', 5,
6
) DESC ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW)
AS "cmc_status_numbers"
FROM ATTRIBUTES
WHERE attribute_type_id IN (
SELECT attribute_type_id
FROM attribute_types
WHERE name_display_code =
'RD')
AND VALUE IN
('Mature', 'Review', 'Final Draft',
'Final Comment', 'Final Document', 'Archived')
AND object_id IN (SELECT obj_id
FROM docs)
GROUP BY VALUE) a1 ON sta."status1" =
a1."progress_CMC_status"
)
ORDER BY DECODE ("progress_CMC_status",
'Mature Draft', 0,
'Review', 1,
'Final Draft', 2,
'Final Comment', 3,
'Final Document', 4,
'Archived Document', 5,
6
)
CREATE TABLE ATTRIBUTES
(
object_id NUMBER(4),
attribute_type_id NUMBER(4),
name_display_code VARCHAR2(5),
VALUE VARCHAR2(25)
);
begin
insert into attributes values (101,201,'RMD','A100');
insert into attributes values (102,201,'RMD','A200');
insert into attributes values (103,201,'RMD','A300');
insert into attributes values (104,200,'RD','Mature');
insert into attributes values (105,200,'RD','Mature');
insert into attributes values (106,200,'RD','Mature');
insert into attributes values (107,200,'RD','Mature');
insert into attributes values (108,200,'RD','Mature');
insert into attributes values (109,200,'RD','Archived');
insert into attributes values (110,200,'RD','Archived');
insert into attributes values (111,200,'RD','Archived');
insert into attributes values (112,200,'RD','Archived');
insert into attributes values (113,200,'RD','Mature');
insert into attributes values (114,200,'RD','Mature');
insert into attributes values (115,200,'RD','Mature');
insert into attributes values (116,200,'RD','Mature');
insert into attributes values (117,200,'RD','Final Document');
insert into attributes values (118,200,'RD','Final Document');
insert into attributes values (119,201,'RMD','A400');
insert into attributes values (120,201,'RMD','A500');
end;
/
CREATE TABLE docs
(
obj_id NUMBER(4)
);
BEGIN
INSERT INTO docs
VALUES (100);
INSERT INTO docs
VALUES (104);
INSERT INTO docs
VALUES (109);
INSERT INTO docs
VALUES (117);
INSERT INTO docs
VALUES (118);
INSERT INTO docs
VALUES (119);
INSERT INTO docs
VALUES (120);
END;
/
CREATE TABLE attribute_types
(
attribute_type_id NUMBER(4),
name_display_code VARCHAR2(5)
);
INSERT INTO attribute_types
VALUES (200, 'RD');
INSERT INTO attribute_types
VALUES (201, 'RMD');
你好，伊戈尔，谢谢你的回答。这里我需要左连接来提取丢失的数据。@ravt-用我的子查询替换你的子查询（在左连接下）。嗨，我试过了，但没有成功。。假设job有奖金@ravt-我需要样本数据来了解您的问题所在。@ravt-您应该在上层选择中计算
sum（）over（）ordr=6程序员的工作，这会对您的结果产生什么影响？对不起。。。我忘了将筛选器放在作业所在的位置（这6个作业），只需拉出6个值。如果需要，我将更新查询。无需执行此操作；可能还有一两个问题。我会看看我能不能想出点什么。ravt-你能按照下面@EgorSkriptunoff的要求发布一些样本数据吗？最好发布一些EMP
记录，并确保其中至少有两个具有相同的作业
，以及您发布的记录的预期结果。嗨，我添加了一些示例数据。
WITH sta AS
(SELECT 'Mature' "status1" FROM DUAL UNION
SELECT 'Review' FROM DUAL UNION
SELECT 'Final Draft' FROM DUAL UNION
SELECT 'Final Comment' FROM DUAL UNION
SELECT 'Final Document' FROM DUAL UNION
SELECT 'Archived' FROM DUAL)
SELECT
DECODE ("stat",
'Mature', 'Mature Draft',
'Review', 'Review',
'Final Draft', 'Final Draft',
'Final Comment', 'Final Comment',
'Final Document', 'Final Document',
'Archived', 'Archived Document'
) AS "progress_CMC_status",
NVL("progress_cmc_status_numbers", 0) AS "progress_cmc_status_numbers",
SUM (NVL("progress_cmc_status_numbers", 0)) OVER (ORDER BY
-DECODE ("stat",
'Mature', 0,
'Review', 1,
'Final Draft', 2,
'Final Comment', 3,
'Final Document', 4,
'Archived', 5,
6)
) AS "cmc_status_numbers"
FROM
(
SELECT
"status1" AS "stat",
"progress_cmc_status_numbers"
FROM
sta
LEFT JOIN (
SELECT
VALUE AS "progress_CMC_status",
COUNT (*) AS "progress_cmc_status_numbers"
FROM ATTRIBUTES
WHERE
attribute_type_id IN (
SELECT attribute_type_id
FROM attribute_types
WHERE name_display_code = 'RD'
)
AND VALUE IN ('Mature', 'Review', 'Final Draft',
'Final Comment', 'Final Document', 'Archived')
AND object_id IN (SELECT obj_id FROM docs)
GROUP BY VALUE
) a1 ON sta."status1" = a1."progress_CMC_status"
)
ORDER BY DECODE ("progress_CMC_status",
'Mature Draft', 0,
'Review', 1,
'Final Draft', 2,
'Final Comment', 3,
'Final Document', 4,
'Archived Document', 5,
6)