Parse platform 如何在解析云代码和客户端之间正确传递参数？（httpRequest示例）

我已经看过一些例子，阅读了文档和其他问题，但是我仍然不确定在哪里添加/正确添加要在云代码和客户端之间正确传递的参数

例如，这里我在云代码中从一个httpRequest创建一个新类

Parse.Cloud.run('POSTfromCloud', {}, {
        success: function(result) {
          console.log("Posted a new Parse Class from Cloud Code Successfully! :"+ JSON.stringify(result))
        },
        error: function(error) {
        console.log("Oops! Couldn't POST from Cloud Code successfully..  :"+ error)
        }
      });
    }

      var myvalue = "I'm The VALUE";
      Parse.Cloud.run('POSTfromCloud', {myValue: myvalue}, {

          success: function(result) {

在我的云代码中main.js

Parse.Cloud.define("POSTfromCloud", function(request, response) {

   //runs when Parse.Cloud.run("POSTfromCloud") on the client side is called
   Parse.Cloud.httpRequest({
        method: "POST",
        headers: {
          "X-Parse-Application-Id": "[PARSE_APP_ID]",
          "X-Parse-REST-API-Key": "[PARSE_REST_ID]",
          "Content-Type": "application/json"
       },

       //adds a new class to my parse data
       url: "https://api.parse.com/1/classes/newPOSTfromCloudClass/",


       body: {
               "newPOSTfromCloudClass": {"key1":"value1","key2":"value2"}
             },

       success: function (httpResponse) {
                console.log(httpResponse.text);
                response.success(httpResponse);
       },
       error:function (httpResponse) {
                console.error('Request failed with response code ' + httpResponse.status);
                response.error(httpResponse.status);
       }

    });  //end of Parse.Cloud.httpRequest()

});

在我的客户方面

Parse.Cloud.run('POSTfromCloud', {}, {
        success: function(result) {
          console.log("Posted a new Parse Class from Cloud Code Successfully! :"+ JSON.stringify(result))
        },
        error: function(error) {
        console.log("Oops! Couldn't POST from Cloud Code successfully..  :"+ error)
        }
      });
    }

      var myvalue = "I'm The VALUE";
      Parse.Cloud.run('POSTfromCloud', {myValue: myvalue}, {

          success: function(result) {

我的结果：

---

砰！正确地工作了。现在让我们假设我想让我的url成为传递的许多参数之一，我该怎么做

当我问这个问题时，我也在修补一些东西，因为我不能正确地传递任何东西（或者它将作为空值返回），所以这里我有一个示例，说明如何将参数传递到这个函数中

在my cloudcode main.js中

Parse.Cloud.define("POSTfromCloud", function(request, response) {

         //HERE- make a new instance of 'myValue' for Cloudcode to handle
         var myValue = request.params.myValue;

       Parse.Cloud.httpRequest({
            method: "POST",
....[blah blah]

            //AND HERE- placed that here in my body, **note:** you shouldnt store tokens like this, ignore what I named it
            body: {
                   "newPOSTfromCloudClass": {"yourToken":myValue,"key2":"value2"}
                 },

客户端

Parse.Cloud.run('POSTfromCloud', {}, {
        success: function(result) {
          console.log("Posted a new Parse Class from Cloud Code Successfully! :"+ JSON.stringify(result))
        },
        error: function(error) {
        console.log("Oops! Couldn't POST from Cloud Code successfully..  :"+ error)
        }
      });
    }

      var myvalue = "I'm The VALUE";
      Parse.Cloud.run('POSTfromCloud', {myValue: myvalue}, {

          success: function(result) {

结果：这应该正确传递参数。再次忽略我使用的标题“yourToken”，你不应该像那样存储令牌

---

这花了一段时间来整理，我希望这能帮助一些人。

当我问这个问题时，我也在修补一些东西，因为我不能正确地传递任何东西（或者它会返回为空值），所以这里我有一个示例，说明了如何将参数传递到这个函数中

在my cloudcode main.js中

Parse.Cloud.define("POSTfromCloud", function(request, response) {

         //HERE- make a new instance of 'myValue' for Cloudcode to handle
         var myValue = request.params.myValue;

       Parse.Cloud.httpRequest({
            method: "POST",
....[blah blah]

            //AND HERE- placed that here in my body, **note:** you shouldnt store tokens like this, ignore what I named it
            body: {
                   "newPOSTfromCloudClass": {"yourToken":myValue,"key2":"value2"}
                 },

客户端

Parse.Cloud.run('POSTfromCloud', {}, {
        success: function(result) {
          console.log("Posted a new Parse Class from Cloud Code Successfully! :"+ JSON.stringify(result))
        },
        error: function(error) {
        console.log("Oops! Couldn't POST from Cloud Code successfully..  :"+ error)
        }
      });
    }

      var myvalue = "I'm The VALUE";
      Parse.Cloud.run('POSTfromCloud', {myValue: myvalue}, {

          success: function(result) {

结果：这应该正确传递参数。再次忽略我使用的标题“yourToken”，你不应该像那样存储令牌

这需要一段时间来整理，我希望这可以帮助别人