Php 如何简化Laravel ORM

对不起，这是个愚蠢的问题

我使用控制器，有很多ORM，我想精简这段代码

我的管制员

public function news(Request $request)
{
    $history = Recruitments_status::where('recruitments_status.status',1)->get();
    $history_a =  Recruitments_status::where('recruitments_status.status',2)->get();
    $history_b = Recruitments_status::where('recruitments_status.status',3)->get();  
    $history_c = Recruitments_status::where('recruitments_status.status',4)->get(); 
    $history_d = Recruitments_status::where('recruitments_status.status',5)->get(); 
    $history_e = Recruitments_status::where('recruitments_status.status',6)->get(); 

    return view('pl_sidebar/news',[
          'history' => $history,
          'history_a' => $history_a,
          'history_b' => $history_b,
          'history_c' => $history_c,
          'history_d' => $history_d,
          'history_e' => $history_e
    ]);
}

如何简化此ORM代码的流程？

使用

所以

---

您的代码将生成多个查询，这是一种糟糕的做法。您可以获得一个集合：

public function news(Request $request)
{
    return view('pl_sidebar/news', [
        'history' => Recruitments_status::whereIn('status', [1, 2, 3, 4, 5, 6])
    ]);
}

@foreach ($history->where('status', 1) as $single)
     {{ $single->status }}
     {{ $single->id }}
@endforeach

然后在刀片模板中使用此集合：

public function news(Request $request)
{
    return view('pl_sidebar/news', [
        'history' => Recruitments_status::whereIn('status', [1, 2, 3, 4, 5, 6])
    ]);
}

@foreach ($history->where('status', 1) as $single)
     {{ $single->status }}
     {{ $single->id }}
@endforeach

---

精简代码的目的是什么？你认为哪里不对？你想达到什么目的？@Wader谢谢你的回复，我的代码太长，有很多查询，我想精简这个代码..哦！　非常感谢你！这是一个很大的帮助！