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Php 向用户的电子邮件发送一份联系表副本_Php_Email - Fatal编程技术网

Php 向用户的电子邮件发送一份联系表副本

Php 向用户的电子邮件发送一份联系表副本,php,email,Php,Email,这与联系方式有关。我正在尝试发送一份电子邮件副本给用户也 所以我想替换相同的函数,所以我第二次重复了if(!isset($hasError))并将$emailTo=$email 这是行不通的。我想标题可能有问题。。。我可以写两个不同的标题标签吗 // to me if(!isset($hasError)) { $emailTo = 'myemail@website.com'; $subject = 'Submitted message f

这与联系方式有关。我正在尝试发送一份电子邮件副本给用户也

所以我想替换相同的函数,所以我第二次重复了
if(!isset($hasError))
并将
$emailTo=$email

这是行不通的。我想标题可能有问题。。。我可以写两个不同的标题标签吗

// to me        
    if(!isset($hasError)) {

        $emailTo = 'myemail@website.com';
        $subject = 'Submitted message from '.$name;
        $sendCopy = trim($_POST['sendCopy']);
        $body = "Name: $name \n\nEmail: $email \n\nComments: $comments";
        $headers = 'From: ' .' <'.$emailTo.'>' . "\r\n" . 'Reply-To: ' . $email;

        mail($emailTo, $subject, $body, $headers);

        $emailSent = true;
    }

//User Copy

if(!isset($hasError)) {
    $emailTo  = '$email';
    $subject = 'Thank you for Contacting';

    $body = "Here is your copy of email which you have sent us. \n\nName: $name \n\nEmail: $email \n\nComments: $comments \n\n Thank you for your email. we will get back to your soon";

    $headers = 'From: ' .' <'.$emailTo.'>' . "\r\n" . 'Reply-To: ' . $email;

     mail($emailTo, $subject, $body, $headers);

    $UserEmailSent = true;

}
//给我
如果(!isset($hasError)){
$emailTo=myemail@website.com';
$subject='从'.$name'提交的邮件;
$sendCopy=trim($_POST['sendCopy']);
$body=“Name:$Name\n\nEmail:$email\n\n注释:$comments”;
$headers='发件人:'.'\r\n'.'回复:'.$email;
邮件($emailTo、$subject、$body、$headers);
$emailSent=true;
}
//用户副本
如果(!isset($hasError)){
$emailTo='$email';
$subject='谢谢联系';
$body=“这是您发送给我们的电子邮件副本。\n\n名称:$name\n\nEmail:$email\n\n建议:$comments\n\n感谢您的电子邮件。我们将很快回复您的邮件”;
$headers='发件人:'.'\r\n'.'回复:'.$email;
邮件($emailTo、$subject、$body、$headers);
$UserEmailSent=true;
}

标题上的哈希是什么?@DontVoteMeDown啊!很抱歉我认为这些可以很容易地解释我的问题,只要看这句话……一点也不。我们不习惯在标题上看到它,另外,不需要在标题上使用PHP脚本,我们已经在标签上看到了它。最简单的标题是最好的。为了清晰起见,我进行了编辑,希望你喜欢。@DontVoteMeDown up投你一票:)