Php Symfony 3 FormType-通过选项数组的实体
我想知道如何正确地传递实体和createForm函数中的另一个变量 让我解释一下,我想这样做:Php Symfony 3 FormType-通过选项数组的实体,php,arrays,forms,symfony,entity,Php,Arrays,Forms,Symfony,Entity,我想知道如何正确地传递实体和createForm函数中的另一个变量 让我解释一下,我想这样做: $repo = $em->getRepository('ProjectBundle:Organisation\Organisation'); $list = $repo->children($this->getUser()->getOrganisation()); $form = $this->createForm('Pro
$repo = $em->getRepository('ProjectBundle:Organisation\Organisation');
$list = $repo->children($this->getUser()->getOrganisation());
$form = $this->createForm('ProjectBundle\Form\Robot\RobotType', array($entity,$list));
我需要向FormType传递另一个变量,因此我直接使用数组
我的表单类型:
<?php
namespace ProjectBundle\Form\Robot;
use ProjectBundle\Entity\Robot\Robot;
use ProjectBundle\Form\User\UserType;
use Symfony\Component\Form\AbstractType;
use Symfony\Component\Form\Extension\Core\Type\ChoiceType;
use Symfony\Component\Form\FormBuilderInterface;
use Symfony\Component\OptionsResolver\OptionsResolver;
class RobotType extends AbstractType
{
/**
* {@inheritdoc}
*/
public function buildForm(FormBuilderInterface $builder, array $options)
{
$builder->add('serial_number')
->add('shell_color',ChoiceType::class,array(
'choices' => Robot::getArrayShellColor()
))
->add('tray1Color',ChoiceType::class,array(
'choices' => Robot::getTrayColor()
))
->add('tray2Color',ChoiceType::class,array(
'choices' => Robot::getTrayColor()
))
->add('tray3Color',ChoiceType::class,array(
'choices' => Robot::getTrayColor()
))
->add('hasBattery')
->add('volume')
->add('organisation',null,array('choices' => $options['data'][1]));
}
/**
* {@inheritdoc}
*/
public function configureOptions(OptionsResolver $resolver)
{
$resolver->setDefaults(array(
'data_class' => 'ProjectBundle\Entity\Robot\Robot'
));
}
/**
* {@inheritdoc}
*/
public function getBlockPrefix()
{
return 'projectbundle_robot_new';
}
}
这是正常的,因为现在我在数组中传递它,现在是我的变量$options['data'][0]
包含了我的对象
怎么办?
谢谢您应该将ProjectBundle\Entity\Robot\Robot Entity作为第二个参数传递给createForm方法,并将options数组作为第三个参数传递给createForm方法
$form = $this->createForm('ProjectBundle\Form\Robot\RobotType', $entity, array($list));
检查EntityType和参数query\u builder
$form = $this->createForm('ProjectBundle\Form\Robot\RobotType', $entity, array($list));