Warning: file_get_contents(/data/phpspider/zhask/data//catemap/1/php/279.json): failed to open stream: No such file or directory in /data/phpspider/zhask/libs/function.php on line 167

Warning: Invalid argument supplied for foreach() in /data/phpspider/zhask/libs/tag.function.php on line 1116

Notice: Undefined index: in /data/phpspider/zhask/libs/function.php on line 180

Warning: array_chunk() expects parameter 1 to be array, null given in /data/phpspider/zhask/libs/function.php on line 181

Warning: file_get_contents(/data/phpspider/zhask/data//catemap/3/html/75.json): failed to open stream: No such file or directory in /data/phpspider/zhask/libs/function.php on line 167

Warning: Invalid argument supplied for foreach() in /data/phpspider/zhask/libs/tag.function.php on line 1116

Notice: Undefined index: in /data/phpspider/zhask/libs/function.php on line 180

Warning: array_chunk() expects parameter 1 to be array, null given in /data/phpspider/zhask/libs/function.php on line 181
Php 从数据库加载html表单,但将第一个选项留空_Php_Html_Sql_Forms - Fatal编程技术网

Php 从数据库加载html表单,但将第一个选项留空

Php 从数据库加载html表单,但将第一个选项留空,php,html,sql,forms,Php,Html,Sql,Forms,我有一个从数据库中选择数据的表单。我希望第一个选项为空(我创建了一个“空”数据库行,但正确的方法是什么 <select id="spolecnost" name="spolecnost"> <?php $result=mysqli_query($connection, "select * from spolecnosti order by nazev;"); while($row=mysqli_fetch_array($result)) { ?> <option&g

我有一个从数据库中选择数据的表单。我希望第一个选项为空(我创建了一个“空”数据库行,但正确的方法是什么

<select id="spolecnost" name="spolecnost">
<?php
$result=mysqli_query($connection, "select * from spolecnosti order by nazev;");
while($row=mysqli_fetch_array($result))
{
?>
<option><?php echo $row["nazev"]; ?></option>

在循环查询结果之前,输出一个空选项行

<select id="spolecnost" name="spolecnost">
<option>-- Select an option --</option>
<?php
$result=mysqli_query($connection, "select * from spolecnosti order by nazev;");
while($row=mysqli_fetch_array($result))
{
?>
<option><?php echo $row["nazev"]; ?></option>

--选择一个选项--
你可以用任何你喜欢的东西来代替它

--选择一个选项--

当然