Php mysql-通过选择每个用户的名称来统计其状态
我有一个包含学生姓名、当前日期和时间及其状态的表,如下所示 约翰有三天缺席 简有两天缺席 我有这个代码,但它计算所有缺席,不为特定的用户,所以我想只显示约翰缺席日和简缺席日,如果我在下拉菜单中选择它Php mysql-通过选择每个用户的名称来统计其状态,php,mysql,select,count,Php,Mysql,Select,Count,我有一个包含学生姓名、当前日期和时间及其状态的表,如下所示 约翰有三天缺席 简有两天缺席 我有这个代码,但它计算所有缺席,不为特定的用户,所以我想只显示约翰缺席日和简缺席日,如果我在下拉菜单中选择它 <?php $sql = "SELECT student_name, count(status) as numberOfabsent FROM attendance WHERE status = 'Absent' GROUP BY student_name"; $result
<?php
$sql = "SELECT student_name, count(status) as numberOfabsent FROM attendance WHERE status = 'Absent' GROUP BY student_name";
$result = $db->prepare($sql);
$result->execute();
while ($row = $result->fetch())
echo $row['numberOfabsent'];
?>
可能在末尾添加having子句,作为在('John','jane')或where条件中包含学生名。可能选择学生名,将(*)计数为numberOfEmission…
<?php
$sql = "SELECT *, count(status) as numberOfabsent FROM attendance WHERE status = 'Absent' GROUP BY student_name";
$result = $db->prepare($sql);
$result->execute();
while ($row = $result->fetch()) {
$numberOfabsent = $row['numberOfabsent'];
$absdate = $row['timestamp'];
echo "<tr><td><a href='" . $configs->getConfig('WEB_ROOT') . "admin/adminuseredit.php?usertoedit=" . $row['student_name'] . "'>" . $row['student_name'] . "</a></td>"
. "<td><div class='shorten'><a href='" . $row['numberOfabsent'] . "'>" . $numberOfabsent . " days</a></div></td><td>" . $absdate . "</td>"
. "<td class='text-center'><div class='btn-group btn-group-xs'><a href='".$configs->getConfig('WEB_ROOT')."admin/adminuseredit.php?usertoedit=".$row['student_name']."' title='Edit' class='open_modal btn btn-default'><i class='fa fa-pencil'></i> View</a>";
echo"</tr>";
}
?>