Php 在搜索中显示mysql内容_Php_Mysql

Php 在搜索中显示mysql内容

php mysql

Php 在搜索中显示mysql内容,php,mysql,Php,Mysql,好的，我有一个连接到数据库的小字典程序。用户可以将单词添加到数据库中，删除单词，然后（在一个完美的世界中）搜索所有现有的单词，并在屏幕上查看他们正在查找的定义。最后一点就是问题所在。我不知道如何搜索数据库中的所有现有单词，并将我要查找的单词放在输入的上方。如何显示搜索结果代码如下： <?php $link = //here is where my database connection info would go if (mysqli_connect_error())

好的，我有一个连接到数据库的小字典程序。用户可以将单词添加到数据库中，删除单词，然后（在一个完美的世界中）搜索所有现有的单词，并在屏幕上查看他们正在查找的定义。最后一点就是问题所在。我不知道如何搜索数据库中的所有现有单词，并将我要查找的单词放在

输入的上方。如何显示搜索结果
代码如下：
<?php

    $link = //here is where my database connection info would go
    if (mysqli_connect_error()) {

        die("Could not connect to database");

    }


    if(isset($_POST['add'])){
        $mysqli = //here is where my database connection info would go
        $sql = "INSERT INTO users ( word,def) VALUES ( '{$mysqli->real_escape_string($_POST['word'])}', '{$mysqlii->real_escape_string($_POST['def'])}' )";
        $insert = $mysqli->query($sql);
        header("Refresh:0");

    }

    if(isset($_POST['delete'])){
        $mysqli = //here is where my database connection info would go
        $command = "DELETE FROM users WHERE `word`='{$mysqli->real_escape_string($_POST['delete-word'])}' or `def`= '{$mysqli->real_escape_string($_POST['delete-def'])}' ";
        $delete = $mysqli->query($command);
        header("Refresh:0");

    }

    if(isset($_POST['search'])){
        //this is where the code would go to search the database and output the answer on the screen.

    }



 ?>

<html>
<head>
<link rel="stylesheet" type="text/css" href="style.css">
<title>Dictionary search</title>
</head>
<body>

<form class = "forms" method = "post" action = "index.php">
<input type = "text" name = "word" placeholder="Add Word...">
<input type = "text" name = "def" placeholder="Add Definition...">
<input type = "submit" name = "add" value = "Add">
</form><br>

<form class = "forms"  method = "post" action = "index.php">
<input  type = "text" name = "delete-word" placeholder="Delete Word...">
<input type = "text" name = "delete-def" placeholder="Delete     Definition...">
<input type = "submit" name = "delete" value = "Delete">
</form>

<form class = "forms"  method = "post" action = "">
<input  type = "text" name = "search-word" placeholder="Look Up Word...">
<input type = "text" name = "search-def" placeholder="Look Up Definition...">
<input type = "submit" name = "search" value = "Search Dictionary">
</form>
</body>
</html>

HTML以获取搜索字符串
<form method="POST" action="someurl.php">
<input type="search" name="search-string">
<input type="submit" value="Search">
</form>

用HTML显示结果的代码
<?php if (count($rows) > 0) : ?>
<dl>
    <?php foreach ($rows as $r) : ?>
        <dt><?= htmlentities($r['word']) ?></dt>
        <dd><?= htmlentities($r['def']) ?></dd>
    <?php endforeach ?>
</dl>
<?php endif ?>

首先，您应该更多地了解PHP，并开始学习PHP中的OOP编码。第二，在代码中使用HTML5！（我在回答这个问题时没有用到它，请在谷歌上搜索更多关于HTML5的信息。）第三，我已经根据你的要求更新了你的代码，但仍然不是最好的做法
index.php
文件：
        <?php

            $link = //here is where my database connection info would go
            if (mysqli_connect_error()) {
                die("Could not connect to database");
            }

            if(isset($_POST['add'])){
                $mysqli = //here is where my database connection info would go

                $word = $mysqli->real_escape_string($_POST['word']);
                $def = $mysqli->real_escape_string($_POST['def']);

                $sql = "INSERT INTO users (word,def) VALUES (".$word.",".$def.")";
                $insert = $mysqli->query($sql);
                if ($insert) {
                    echo 'success';
                } else {
                    echo 'error';
                }
            }

            if(isset($_POST['delete'])){
                $mysqli = //here is where my database connection info would go

                $word = $mysqli->real_escape_string($_POST['delete-word']);
                $def = $mysqli->real_escape_string($_POST['delete-def']);

                $sql = "DELETE FROM users WHERE `word`='".$word."' OR `def`='".$def."'";
                $delete = $mysqli->query($sql);
                if ($delete) {
                    echo 'success';
                } else {
                    echo 'error';
                }
            }
        ?>

        <html>
        <head>
        <link rel="stylesheet" type="text/css" href="style.css">
        <title>Dictionary search</title>
        </head>
        <body>

        <form class="forms" method="post" action="index.php">
        <input type="text" name="word" placeholder="Add Word...">
        <input type="text" name="def" placeholder="Add Definition...">
        <input type="submit" name="add" value="Add">
        </form><br>

        <form class="forms"  method="post" action="index.php">
        <input  type="text" name="delete-word" placeholder="Delete Word...">
        <input type="text" name="delete-def" placeholder="Delete Definition...">
        <input type="submit" name="delete" value="Delete">
        </form>

        <form class="forms"  method="post" action="search.php">
        <input type="text" name="search-word" placeholder="Look Up Word...">
        <input type="text" name="search-def" placeholder="Look Up Definition...">
        <input type="submit" name="search" value="Search Dictionary">
        </form>
        </body>
        </html>

        <html>
<body>
    <?php
if(isset($_POST['search'])){
    //this is where the code would go to search the database and output the answer on the screen.
    $mysqli = //here is where my database connection info would go

    $search_w = $mysqli->real_escape_string($_POST['search-word']);
    $search_d = $mysqli->real_escape_string($_POST['search-def']);

    $sql = "SELECT FROM `users` WHERE `word`='' OR `def`=''";
    $result = $mysqli->query($sql);
    $rows = [];
    while ($row = $result->fetch_assoc()) :
        $rows[] = $row;
        ?>
        <p><?php echo $row; ?></p>
    <?php endwhile;
}
?>
    </body>
</html>

if（isset（$\u POST['search']））{
$mysqli=//下面是我的数据库连接信息
$command=“SELECT*来自以下用户：`word`='{$mysqli->real\u escape\u string（$\u POST['search']）}'或`def`='{$mysqli->real\u escape\u string（$\u POST['search']）}'；
$select=$mysqli->query（$command）；
如果（$select->num\u rows>0）{
//每行的输出数据
而（$row=$select->fetch_assoc（））{
回显“Word:.$row[“Word”]。$row[“def”]。
”；
}
}否则{
回显“0结果”；
}
}
$mysqlii->real\u escape\u string
onei太多了是的。哈哈。有没有关于如何搜索数据库并输出响应的想法？使用select sql命令并循环其结果集并打印结果。从表格中选择def，其中word='searched word'对不起，这里太乱了。我在Windows操作系统，这不是我的编码环境。另外，请下次学习PDO而不是mysqli，甚至mysql；）非常感谢。很高兴知道。谢谢你！那有帮助@欢迎光临。感谢你的支持投票。谢谢，谢谢！非常有用。
        <html>
<body>
    <?php
if(isset($_POST['search'])){
    //this is where the code would go to search the database and output the answer on the screen.
    $mysqli = //here is where my database connection info would go

    $search_w = $mysqli->real_escape_string($_POST['search-word']);
    $search_d = $mysqli->real_escape_string($_POST['search-def']);

    $sql = "SELECT FROM `users` WHERE `word`='' OR `def`=''";
    $result = $mysqli->query($sql);
    $rows = [];
    while ($row = $result->fetch_assoc()) :
        $rows[] = $row;
        ?>
        <p><?php echo $row; ?></p>
    <?php endwhile;
}
?>
    </body>
</html>

if(isset($_POST['search'])){
    $mysqli = //here is where my database connection info would go
    $command = "SELECT *FROM users WHERE `word`='{$mysqli->real_escape_string($_POST['search'])}' or `def`= '{$mysqli->real_escape_string($_POST['search'])}' ";
    $select = $mysqli->query($command);  

  if ($select->num_rows > 0) {
// output data of each row
while($row = $select->fetch_assoc()) {
    echo "Word: " . $row["word"]. " " . $row["def"]. "<br>";
}
} else {
echo "0 results";
}

}