Php 返回模型中的一行,将其传递给控制器和视图-Codeigniter
很抱歉发布这样一个问题,但我在返回单张时遇到了困难 行并将其传递给模型。以下是我的模型中的方法:Php 返回模型中的一行,将其传递给控制器和视图-Codeigniter,php,codeigniter,Php,Codeigniter,很抱歉发布这样一个问题,但我在返回单张时遇到了困难 行并将其传递给模型。以下是我的模型中的方法: public function test($user_id) { $query = $this->db->query("SELECT COUNT(*) AS test FROM test WHERE user_id = '.$user_id.'"); return $query->first_row('array'); } class MY_Controller
public function test($user_id)
{
$query = $this->db->query("SELECT COUNT(*) AS test FROM test WHERE user_id = '.$user_id.'");
return $query->first_row('array');
}
class MY_Controller extends CI_Controller
{
public $layout;
public $id;
public $data = array();
public function __construct()
{
parent::__construct();
$this->output->nocache();
$this->load->model('subject_model');
$this->load->model('user_model');
$this->load->model('survey_model');
$this->id = $this->session->userdata('user_id');
$this->data['check_if_already_posted_it_survey'] = $this->survey_model->checkIfAlreadyPostedSurvey('it_survey', $this->id);
$this->data['check_if_already_posted_lvis_survey'] = $this->survey_model->checkIfAlreadyPostedSurvey('lvis_survey', $this->id);
$this->data['test']= $this->survey_model->test($this->id);
$this->layout = 'layout/dashboard';
}
下面是我的控制器的一个示例,其中包含来自我的模型的一些其他返回值:
public function test($user_id)
{
$query = $this->db->query("SELECT COUNT(*) AS test FROM test WHERE user_id = '.$user_id.'");
return $query->first_row('array');
}
class MY_Controller extends CI_Controller
{
public $layout;
public $id;
public $data = array();
public function __construct()
{
parent::__construct();
$this->output->nocache();
$this->load->model('subject_model');
$this->load->model('user_model');
$this->load->model('survey_model');
$this->id = $this->session->userdata('user_id');
$this->data['check_if_already_posted_it_survey'] = $this->survey_model->checkIfAlreadyPostedSurvey('it_survey', $this->id);
$this->data['check_if_already_posted_lvis_survey'] = $this->survey_model->checkIfAlreadyPostedSurvey('lvis_survey', $this->id);
$this->data['test']= $this->survey_model->test($this->id);
$this->layout = 'layout/dashboard';
}
我可以将该数据数组中的所有值传递给我的视图,但“test”除外。我基本上什么都试过了
CheckIfAlreadyPostedSurvey方法将返回
具有num_行的行数,我可以通过写入以下内容在视图中轻松打印其中的值:
<?=$check_if_already_posted_it_survey?>
在我看来,我应该如何打印出“测试”
提前感谢并道歉…我可能问错了,但你试过了吗
echo $this->survey_model->test($this->id);
试试这个:
public function test($user_id)
{
$query = $this->db->query("SELECT COUNT(*) AS test FROM test WHERE user_id = '".$user_id."'");
return $query->row()->test;
}
这将返回一行作为对象,然后返回引用的行名称,在本例中为test
以下内容也将起作用
public function test($user_id)
{
$query = $this->db->query("SELECT * FROM test WHERE user_id = '".$user_id."'");
return count($query->result());
}
您还弄乱了SQL语句中的引号